Angular $ q返回承诺多个$ http调用

byr*_*rdr 6 angularjs angular-promise

我正在进行$ http调用,它遍历多个api中的每一个并返回一个对象中的所有数据.我通常已经准备好在$ http调用时解决.与此类似:

function getAllData(api) {
    return $http({
        method: 'GET',
        url: '/api/' + api
    })
    .then(sendResponseData)
    .catch (sendGetVolunteerError);
}
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当前函数我遍历每个api并将api中的每个对象推送到一个数组中,然后将其推送到整个数组中.我有这个功能,返回一个多维数组,需要被展平.

我想在承诺中归还这个,但我要回来了undefined.这是我到目前为止的情况?有没有更好的方法来解决这个问题?

DataService的:

function getSearchData() {
    return {
        loadDataFromUrls: function () {
            var apiList = ["abo", "ser", "vol", "con", "giv", "blo", "par"];
            var deferred = $q.defer();
            var log = [];
            angular.forEach(apiList, function (item, key) {
                var logNew = [];
                $http({
                    method: 'GET',
                    url: '/api/' + item
                }).then(function (response) {
                    angular.forEach(response.data, function (item, key) {
                        this.push(item);
                    }, logNew);
                    return logNew;
                });
                this.push(logNew);
            }, log);
            $q.all(log).then(

            function (results) {
                deferred.resolve(
                JSON.stringify(results))
            },

            function (errors) {
                deferred.reject(errors);
            },

            function (updates) {
                deferred.update(updates);
            });
            return deferred.promise;
        }
    };
};
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控制器:

function getSearchData(){
  return dataService.getSearchData.loadDataFromUrls;
}  

$scope.searchData = getSearchData();
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JLR*_*she 16

$q.allmap函数是你需要的:

function getSearchData() {
    return {
        // returns a promise for an object like:
        // { abo: resultFromAbo, ser: resultFromSer, ... }
        loadDataFromUrls: function () {
            var apiList = ["abo", "ser", "vol", "con", "giv", "blo", "par"];

            return $q.all(apiList.map(function (item) {
                return $http({
                    method: 'GET',
                    url: '/api/' + item
                });
            }))
            .then(function (results) {
                var resultObj = {};
                results.forEach(function (val, i) {
                    resultObj[apiList[i]] = val.data;
                });
                return resultObj;        
            });
        }
    };
}
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