在Swift中解码JSON Web令牌

and*_*yen 8 base64 ios jwt swift

尝试在Swift中解码JWT有效负载并且遇到非常困难的时间

static func decodePayload(tokenstr: String) {

    //splitting JWT to extract payload
    let arr = split(tokenstr) {$0 == "."}

    //base64 encoded string i want to decode
    let base64String = arr[1] as String
    println(base64String) //eyJleHAiOjE0MjY4MjIxNjMsImlkIjoiNTUwYjA3NzM4ODk1NjAwZTk5MDAwMDAxIn0

    //attempting to convert base64 string to nsdata 
    let nsdata: NSData = NSData(base64EncodedString: base64String, options: NSDataBase64DecodingOptions(rawValue: 0))

    //decoding fails because nsdata unwraps as nil
    let base64Decoded: NSString = NSString(data: nsdata!, encoding: NSUTF8StringEncoding)!


}
Run Code Online (Sandbox Code Playgroud)

Mar*_*n R 23

eyJleHAiOjE0MjY4MjIxNjMsImlkIjoiNTUwYjA3NzM4ODk1NjAwZTk5MDAwMDAxIn0
Run Code Online (Sandbox Code Playgroud)

不是有效的Base64编码字符串,因为它的长度不是4的倍数.某些Base64解码器容忍此错误,但NSData方法不能.

所以这实际上是服务器端创建Base64编码字符串的错误.如有必要,您可以通过添加带=字符的必需填充(为Swift 2更新的代码)在您的应用中修复它:

var base64String = arr[1] as String
if base64String.characters.count % 4 != 0 {
    let padlen = 4 - base64String.characters.count % 4
    base64String += String(count: padlen, repeatedValue: Character("="))
}
Run Code Online (Sandbox Code Playgroud)

现在解码按预期工作:

if let data = NSData(base64EncodedString: base64String, options: []),
    let str = String(data: data, encoding: NSUTF8StringEncoding) {
    print(str) // {"exp":1426822163,"id":"550b07738895600e99000001"}
}
Run Code Online (Sandbox Code Playgroud)

斯威夫特4:

var base64String = "eyJleHAiOjE0MjY4MjIxNjMsImlkIjoiNTUwYjA3NzM4ODk1NjAwZTk5MDAwMDAxIn0"

if base64String.count % 4 != 0 {
    let padlen = 4 - base64String.count % 4
    base64String.append(contentsOf: repeatElement("=", count: padlen))
}

if let data = Data(base64Encoded: base64String) ,
    let str = String(data: data, encoding: .utf8) {
    print(str) // {"exp":1426822163,"id":"550b07738895600e99000001"}
}
Run Code Online (Sandbox Code Playgroud)