Die*_*ego 3 string split r data.table
我有一个包含2列的数据表:
term freq
1: a arena tour 1
2: a available why 1
3: a backup in 1
4: a bad ass 1
5: a bad chick 1
Run Code Online (Sandbox Code Playgroud)
我想将"term"列拆分为最后一个空格,例如:
termA termB freq
1: a arena tour 1
2: a available why 1
3: a backup in 1
4: a bad chick 1
Run Code Online (Sandbox Code Playgroud)
我尝试使用"str"(代码bellow),它仅对一个字符串起作用,但对data.date不起作用(似乎在所有行上使用相同的索引)
data.table (termA = substr(dt_n3$term, 1, rev(gregexpr("\\ ", dt_n3$term)[[1]])[1]-1),
termB = substr(dt_n3$term, rev(gregexpr("\\ ", dt_n3$term)[[1]])[1], 1000),
freq = dt_n3$freq)
Run Code Online (Sandbox Code Playgroud)
无论如何,我不认为这是最好的方法.有人可以帮我吗?谢谢
您可以尝试v 1.9.5中的tstrsplit功能data.table
DT[, paste0('term', LETTERS[1:2]) := tstrsplit(term, ' (?=[^ ]*$)',
perl=TRUE)][, term:=NULL][]
# freq termA termB
#1: 1 a arena tour
#2: 1 a available why
#3: 1 a backup in
#4: 1 a bad ass
#5: 1 a bad chick
Run Code Online (Sandbox Code Playgroud)
DT <- data.table(term= c("a arena tour", "a available why",
"a backup in", "a bad ass", "a bad chick"), freq=1)
Run Code Online (Sandbox Code Playgroud)
稍微修改过的版本,您可以在同一语句中进行分配和删除:
cols = c("term", paste0("term", LETTERS[1:2]))
DT[, (cols) := c(list(NULL), tstrsplit(term, ' (?=[^ ]*$)', perl=TRUE))]
Run Code Online (Sandbox Code Playgroud)
指定NULL要term删除该列.