我们正在从我们构建的名为DBQuery的gem重构一个名为DataSourceIntegrations的Ruby应用程序.我正在将一些DBQuery代码迁移到DataSourceIntegrations中.我正在构建的部分取决于DBQuery,它将在单独的步骤中添加.
同时,我需要编写RSpec测试来验证是否正确调用了DBQuery代码,所有这些都没有DBQuery.
我有的是:
码-
宝石代码 -
module DBQuery
class Query
MAX = 1000
def retrieve_users
# Returns an array of user IDs
end
end
end
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申请代码 -
module Integration
def initialize
@query = DBQuery::Query.new
end
end
module Integration
class StackOverflowIntegration
include Integration
def query
users = []
while (users < DBQuery::Query::MAX) do
# Creates a users buffer
users.push @query.retrieve_users(users_buffer)
end
end
end
end
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测试─
describe Integration::StackOverflowIntegration do
let(:db_query) { double('DBQuery::Query') }
before do
stub_const('DBQuery::Query::MAX', 1000)
allow(db_query).to receive(:new).and_return(db_query)
allow(db_query).to receive(:retrieve_users).and_return([1000, 1001, 1002])
end
it 'queries without error' do
expect { StackOverflowIntegration.new.query }.to_not raise_error
end
end
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我无法弄清楚如何以不需要DBQuery的方式存根.我的错误是:
NoMethodError:
undefined method `new' for #<Module:0x007fa7ce561968>
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我不知道为什么DBQuery :: Query被表示为模块,或者如何让它识别"new".
据我了解,您希望在DBQuery::Query不在代码中定义它的情况下提出期望.rspec-mocks可以存储未定义的常量,就像你所做的那样DBQuery::Query::MAX.要DBQuery::Query完全存根,首先创建一个类double,并在测试中为它存根一个const:
db_query__query_class = class_double('DBQuery::Query')
stub_const('DBQuery::Query', db_query__query_class)
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这样,DBQuery::Query在你的代码中将返回query_classdouble.然后你可以用它定义一些行为:
query_instance = instance_double('DBQuery::Query')
allow(db_query__query_class).to receive(:new).and_return(query_instance)
allow(db_query).to receive(:retrieve_users).and_return([1000, 1001, 1002])
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您仍然需要存根嵌套常量 DBQuery::Query::MAX
stub_const('DBQuery::Query::MAX', 1000)
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关于样式,我更喜欢放置存根并允许在let/ let!语句中这样:
describe Integration::StackOverflowIntegration do
let!(:db_query__query_class) do
class_double('DBQuery::Query').tap do |double|
stub_const('DBQuery::Query', double)
stub_const('DBQuery::Query::MAX', 1000)
allow(double).to receive(:new).and_return(query_instance)
end
end
let(:query_instance) do
instance_double('DBQuery::Query').tap do |double|
allow(double).to receive(:retrieve_users).and_return([1000, 10001, 1002])
end
end
end
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另外,我喜欢将返回的值放在自己的位置,let以便我可以轻松更改它们.这是一个完整的工作(和虚拟)示例:
RSpec.configure do |c|
c.around(:context, :protect_with_timeout) do |example|
Timeout::timeout(2) {
example.run
}
end
end
describe Integration::StackOverflowIntegration do
let!(:db_query__query_class) do
class_double('DBQuery::Query').tap do |double|
stub_const('DBQuery::Query', double)
stub_const('DBQuery::Query::MAX', max_queries)
allow(double).to receive(:new).and_return(query_instance)
end
end
let(:query_instance) do
instance_double('DBQuery::Query').tap do |double|
allow(double).to receive(:retrieve_users).and_return(retrieved_users)
end
end
let(:max_queries) { 1000 }
let(:retrieved_users) { [1000, 1001, 1002] }
describe '#query' do
subject(:stack_overflow_query) { Integration::StackOverflowIntegration.new.query }
it 'queries without error in nominal case' do
expect { stack_overflow_query }.to_not raise_error
end
context 'with 0 users returned' do
let(:retrieved_users) { [] }
it 'does not loop forever', :protect_with_timeout do
pending('not implemented yet...')
stack_overflow_query # will timeout
end
end
context 'with 10 users returned' do
let(:retrieved_users) { [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] }
it 'calls #retrieve_users 100 times' do
stack_overflow_query
expect(query_instance).to have_received(:retrieve_users).exactly(100).times
end
end
context 'with DBQuery::Query::MAX set to 0' do
let(:max_queries) { 0 }
it 'does not call #retrieve_users at all' do
stack_overflow_query
expect(query_instance).not_to have_received(:retrieve_users)
end
end
end
end
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