我的文字有这些花哨的双引号:'''我想用Ruby gsub和regex用常规双引号替换它们.这是一个例子,我到目前为止:
sentence = 'This is a quote, “Hey guys!”'
I couldn't figure out how to escape double quotes so I tried using 34.chr:
sentence.gsub("“",34.chr). This gets me close but leaves a back slash in front of the double quote:
sentence.gsub("“",34.chr) => 'This is a quote, \"Hey guys!”'
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irb由于打印出语句结果的方式,反斜杠只会显示出来.如果您将gsubed字符串传递给另一个方法,例如puts,您将在转换转义序列后看到"真实"表示.
1.9.0 > sentence = 'This is a quote, “Hey guys!”'
=> "This is a quote, \342\200\234Hey guys!\342\200\235"
1.9.0 > sentence.gsub('“', "'")
=> "This is a quote, 'Hey guys!\342\200\235"
1.9.0 > puts sentence.gsub('“', "'")
This is a quote, 'Hey guys!”
=> nil
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还要注意,输出之后puts,我们看到=> nil指示返回的调用putsnil.
您可能已经注意到有趣的引用仍然在输出的末尾puts:这是因为引号是两个不同的转义序列,我们只命名一个.但我们可以用正则表达式处理gsub:
1.9.0 > puts sentence.gsub(/(“|”)/, 34.chr)
This is a quote, "Hey guys!"
=> nil
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此外,在许多情况下,您可以在Ruby字符串中交换单引号和双引号 - 双引号执行扩展而单引号则不执行扩展.以下几种方法可以获得仅包含双引号的字符串:
1.9.0 > '"' == 34.chr
=> true
1.9.0 > %q{"} == 34.chr
=> true
1.9.0 > "\"" == 34.chr
=> true
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