FOSRestBundle将json数据发布到不起作用的表单

Question

我将JSON数据发布到控制器中的表单.实体没有填写我发送的属性,这里是它的样子:

// Controller

class UserApiController extends FOSRestController
{
    // works fine
    public function cgetAction()
    {
        return $this->get('model.user')->getAllUsers();
    }

    // works fine
    public function getAction($id)
    {
        return $this->get('model.user')->getUserById($id);
    }

    // this method fails
    public function postAction(Request $request)
    {
        $form = $this->createForm(new UserType(), new User());
        $form->bind($request);

        if($form->isValid())
        {
            die('are you valid or not??');
        }

        return $this->view($form, 400);
    }
}

实体看起来像常规实体,也可以形成.

我有一个测试控制器将json数据发送到api:

public function testJsonPostAction()
    {
        $client = static::createClient();
        $client->request(
            'POST',
            '/api/1.0/users',
            array(),
            array(),
            array('CONTENT_TYPE' => 'application/json'),
            '{"firstName": "John", "lastName": "Doe", "emailAddress": "something@somewhere.com", "sex": "1"}'
        );

        var_dump($client->getResponse()->getContent());
    }

并验证:

Software\Bundle\Entity\User:
    properties:
        firstName:
            - NotBlank: ~
            - Length:
                min: 2
                max: 255
        lastName:
            - NotBlank: ~
            - Length:
                min: 2
                max: 255

好吧,问题是$ form始终无效.当我转储$ form-> getData()内容时,我得到了我的用户实体,但是没有填写firstName,lastName等.相反,我明显得到了验证错误,但这是另一个但是:

为什么$ form-> bind($ request)(我知道它已被弃用)返回这个(这更不好):

{"code":400,"message":"Validation Failed","errors":{"children":{"firstName":{"errors":["This value should not be blank."]},"lastName":{"errors":["This value should not be blank."]},"emailAddress":{"errors":["This value should not be blank."]},"sex
":[],"locale":[]}}}

和相同的代码,但使用$ form-> handleRequest($ request)返回:

{"children":{"firstName":[],"lastName":[],"emailAddress":[],"sex":[],"locale":[]}}

有什么不同？因为我认为handleRequest是bind的替代品.我已经尝试过,我认为互联网上的所有解决方案都是不同的,我无法让它发挥作用.FOSRestBundle的文档很差,它说的都是关于获取内容的,但几乎没有关于发布的内容.

任何帮助非常感谢.

Answer 1

由于没有人回复,我将在这个问题上回答自己.

首先,发送的JSON必须以表单名称开头,所以相反:

{"firstName": "John", "lastName": "Doe", "emailAddress": "something@somewhere.com", "sex": "1"

一定是:

{"user": {"firstName": "John", "lastName": "Doe", "emailAddress": "something@somewhere.com", "sex": "1"}}

在我的情况下,表单名称是"用户".

我用过CURL来测试它:

curl -v -H "Accept: application/json" -H "Content-type: application/json" -XPOST -d "{\"user\":{\"firstName\":\"John\", \"emailAddress\": \"somewhere@somehow.com\", \"password\":\"verystrongmuchpower\"}}" http://localhost.software.com/app_dev.php/api/1.0/users

由于我使用CURL测试API,因此bind和handleRequest的响应差异消失了.

如果我得到更多结论,我会尽快更新这个答案.