laravel eloquent JOIN ON多个条件

Question

我有一个表呼银行,存储国家银行名称,代码等

我有一个表呼叫site_banks,它存储银行账户,银行持有人名称和涉及银行的外国bank_id

我有一个表存款deposit_records,存储存款时间,存款收据,状态等,以及涉及site_banks的外国bank_id

对于deposit_records,状态字段,值1表示成功

现在我想计算每个site_banks的总收入

但我不希望每一行site_banks调用一个查询来计算,这将有很多sql查询调用

所以我想我可以使用join,下面是site_banks模型文件,scopeGroupAllSiteBanksByBranch是我想收集所有site_banks,用SUM连接,返回数组的地方

但即使我有大约200个site_banks行,很多deposit_records行,其状态为'1',但scopeGroupAllSiteBanksByBranch将始终只返回一行,我不明白为什么,我复制sql查询在mysql中运行,是同样的结果,只有1行返回.

<?php

use Illuminate\Database\Eloquent\SoftDeletingTrait;

class SiteBanks extends \LaravelBook\Ardent\Ardent {

    use SoftDeletingTrait;

    /**
     * The database table used by the model.
     *
     * @var string
     */
    protected $table = 'site_banks';

    protected $dates = ['deleted_at'];

    protected $fillable = array('bank_id', 'bank_name', 'bank_account', 'bank_holder', 'bank_username', 'bank_password', 'min_deposit', 'max_deposit', 'daily_max_deposit');

    public static $rules = array(
        'bank_id' => 'required|exists:banks,id',
        'bank_name' => 'required|min:1',
        'bank_account' => 'required|min:1|numberonly',
        'bank_holder' => 'required|min:1',
        'bank_username' => 'required|min:1',
        'bank_password' => 'required|min:1',
        'min_deposit' => 'required|fund',
        'max_deposit' => 'required|fund',
        'daily_max_deposit' => 'required|fund',
    );

    public function bank() {
        return $this->belongsTo('Banks', 'bank_id');
    }

    public function transactions() {
        return $this->hasMany('Deposit', 'bank_id', 'id');
    }

    public function transactionsDone() {
        return $this->hasMany('Deposit', 'bank_id', 'id')->where('status', '=', 1);
    }

    public function transactionsBanned() {
        return $this->hasMany('Deposit', 'bank_id', 'id')->where('status', '=', 2);
    }

    public function transactionsPending() {
        return $this->hasMany('Deposit', 'bank_id', 'id')->where('status', '=', 0);
    }

    public function setBankPasswordAttribute($value) {
        $this->attributes['bank_password'] = Crypt::encrypt($value);
    }

    public function getBankPasswordAttribute() {
        return Crypt::decrypt($this->attributes['bank_password']);
    }

    public function scopeGetAvailableBanks($query) {
        $query->where(DB::raw("(current_deposit < daily_max_deposit) OR (current_deposit IS NULL) OR (DATE(last_deposit) != DATE(NOW()) OR last_deposit IS NULL) OR (DATE(last_deposit) = DATE(NOW()) && current_deposit < daily_max_deposit)"));
        $query->groupBy('bank_id')->orderBy('id', 'ASC');
    }

    public function scopeGroupAllSiteBanksByBranch($query) {
        $bank = \SiteBanks::withTrashed()
            ->leftJoin('deposit_records', function($q) {
                $q->on('deposit_records.bank_id', '=', 'site_banks.id');
                $q->where('deposit_records.status', '=', 1, 'and');
            })
            ->select(array('site_banks.*', DB::raw('SUM(`deposit_records`.`deposit_amount`) AS `total_income`')))
            ->get();
//        $bank = \SiteBanks::withTrashed()->get();
        $bank->load('bank');

        $banks = array();
        foreach($bank as $key => $var) {
            $arr = array();

            $arr = $var->toArray();
            $arr['income'] = $var->total_income;
            $banks[$var->bank->bank_name][] = $arr;
        }

        return $banks;
    }

}

SQL查询

选择site_banks*,SUM( deposit_records.deposit_amount)AS total_income从site_banks左联接deposit_records上 deposit_records.bank_id= site_banks.id和 deposit_records.status='1'

var_dump scopeGroupAllBanksByBranch的结果

array (size=1)
  'BANKNAME' => 
    array (size=1)
      0 => 
        array (size=20)
          'id' => int 1
          'bank_id' => int 4
          'bank_name' => string 'BANKNAME' (length=6)
          'bank_account' => string '123456789' (length=9)
          'bank_holder' => string 'ACCOUNT HOLDER NAME' (length=11)
          'bank_username' => string 'username' (length=8)
          'bank_password' => string 'hehethisispassword' (length=18)
          'min_deposit' => string '400.00' (length=6)
          'max_deposit' => string '9999.99' (length=7)
          'daily_max_deposit' => string '25500.00' (length=8)
          'last_deposit' => string '2015-02-05 03:04:00' (length=19)
          'current_deposit' => string '0.00' (length=4)
          'created_by' => int 1
          'updated_by' => null
          'created_at' => string '2015-02-04 08:21:16' (length=19)
          'updated_at' => string '2015-02-04 08:21:16' (length=19)
          'deleted_at' => null
          'total_income' => string '1722.00' (length=7)
          'bank' => 
            array (size=7)
              ...
          'income' => string '1722.00' (length=7)

Answer 1

您可以通过遵循代码解决您的问题

SQL查询

LEFT JOIN bookings  
           ON rooms.id = bookings.room_type_id AND (bookings.arrival = ? OR bookings.departure = ? )

Laravel加入了多种条件

 ->join('bookings', function($join) use ($key1, $key2)
{
    $join->on('rooms.id', '=', 'bookings.room_type_id');
    $join->on(function($query) use ($key1, $key2)
            {
             $query->on('bookings.arrival', '=', $key1);
             $query->orOn('departure', '=',$key2);
            });

})