TSQL - 如何URL编码

Question

寻找一个免费测试的sql脚本,我可以在UDF中使用它来编码通过sql的url.函数将接收URL并传递URL编码的URL.我见过几个,但我遇到的所有东西似乎都有一些缺陷.

Answer 1

Peter DeBetta这个怎么样:

CREATE FUNCTION dbo.UrlEncode(@url NVARCHAR(1024))
RETURNS NVARCHAR(3072)
AS
BEGIN
    DECLARE @count INT, @c NCHAR(1), @i INT, @urlReturn NVARCHAR(3072)
    SET @count = LEN(@url)
    SET @i = 1
    SET @urlReturn = ''    
    WHILE (@i <= @count)
     BEGIN
        SET @c = SUBSTRING(@url, @i, 1)
        IF @c LIKE N'[A-Za-z0-9()''*\-._!~]' COLLATE Latin1_General_BIN ESCAPE N'\' COLLATE Latin1_General_BIN
         BEGIN
            SET @urlReturn = @urlReturn + @c
         END
        ELSE
         BEGIN
            SET @urlReturn = 
                   @urlReturn + '%'
                   + SUBSTRING(sys.fn_varbintohexstr(CAST(@c AS VARBINARY(MAX))),3,2)
                   + ISNULL(NULLIF(SUBSTRING(sys.fn_varbintohexstr(CAST(@c AS VARBINARY(MAX))),5,2), '00'), '')
         END
        SET @i = @i +1
     END
    RETURN @urlReturn
END

Answer 2

这个问题特别要求一个函数，但是如果您无法创建任何函数，这里是一个 url 编码的解决方案：

select replace27
from TableName
cross apply (select replace1 = replace(T.TagText, '%', '%25')) r1
cross apply (select replace2 = replace(replace1, '&', '%26')) r2
cross apply (select replace3 = replace(replace2, '$', '%24')) r3
cross apply (select replace4 = replace(replace3, '+', '%2B')) r4
cross apply (select replace5 = replace(replace4, ',', '%2C')) r5
cross apply (select replace6 = replace(replace5, ':', '%3A')) r6
cross apply (select replace7 = replace(replace6, ';', '%3B')) r7
cross apply (select replace8 = replace(replace7, '=', '%3D')) r8
cross apply (select replace9 = replace(replace8, '?', '%3F')) r9
cross apply (select replace10 = replace(replace9, '@', '%40')) r10
cross apply (select replace11 = replace(replace10, '#', '%23')) r11
cross apply (select replace12 = replace(replace11, '<', '%3C')) r12
cross apply (select replace13 = replace(replace12, '>', '%3E')) r13
cross apply (select replace14 = replace(replace13, '[', '%5B')) r14
cross apply (select replace15 = replace(replace14, ']', '%5D')) r15
cross apply (select replace16 = replace(replace15, '{', '%7B')) r16
cross apply (select replace17 = replace(replace16, '}', '%7D')) r17
cross apply (select replace18 = replace(replace17, '|', '%7C')) r18
cross apply (select replace19 = replace(replace18, '^', '%5E')) r19
cross apply (select replace20 = replace(replace19, ' ', '%20')) r20
cross apply (select replace21 = replace(replace20, '~', '%7E')) r21
cross apply (select replace22 = replace(replace21, '`', '%60')) r22
cross apply (select replace23 = replace(replace22, '*', '%2A')) r23
cross apply (select replace24 = replace(replace23, '(', '%28')) r24
cross apply (select replace25 = replace(replace24, ')', '%29')) r25
cross apply (select replace26 = replace(replace25, '/', '%2F')) r26
cross apply (select replace27 = replace(replace26, '\', '%5C')) r27

此解决方案的局限性在于不能替换 ASCII 控制字符或非 ASCII 字符。

请注意，第一个替换是 % 很重要，因此我们不会转义任何转义码。

Answer 3

为了使用此脚本，您需要使用数字表。

CREATE FUNCTION [dbo].[URLEncode] 
    (@decodedString VARCHAR(4000))
RETURNS VARCHAR(4000)
AS
BEGIN
/******
*       select dbo.URLEncode('K8%/fwO3L mEQ*.}')
**/

DECLARE @encodedString VARCHAR(4000)

IF @decodedString LIKE '%[^a-zA-Z0-9*-.!_]%' ESCAPE '!'
BEGIN
    SELECT @encodedString = REPLACE(
                                    COALESCE(@encodedString, @decodedString),
                                    SUBSTRING(@decodedString,num,1),
                                    '%' + SUBSTRING(master.dbo.fn_varbintohexstr(CONVERT(VARBINARY(1),ASCII(SUBSTRING(@decodedString,num,1)))),3,3))
    FROM dbo.numbers 
    WHERE num BETWEEN 1 AND LEN(@decodedString) AND SUBSTRING(@decodedString,num,1) like '[^a-zA-Z0-9*-.!_]' ESCAPE '!'
END
ELSE
BEGIN
    SELECT @encodedString = @decodedString 
END

RETURN @encodedString

END
GO

该脚本在SQL Server Central上完全可用（需要注册）