SRM*_*RMR 1 iphone objective-c ios parse-platform watchkit
我Parse在我的iPhone应用程序中进行查询,但是在尝试Parse在我的Watch应用程序中执行相同的查询时遇到错误.
这是我的iPhone应用程序中的查询:
- (void)viewDidLoad {
// GMT Date from Phone
NSDate *gmtNow = [NSDate date];
NSLog(@"GMT Now: %@", gmtNow);
// Query Parse
PFQuery *query = [self queryForTable];
[query whereKey:@"dateGame" greaterThanOrEqualTo:gmtNow];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (!error) {
NSMutableArray *localMatchup = [@[] mutableCopy];
for (PFObject *object in objects) {
// Add objects to local Arrays
[localMatchup addObject:[object objectForKey:@"matchup"]];
// App Group
NSString *container = @"group.com.me.off";
NSUserDefaults *defaults = [[NSUserDefaults alloc] initWithSuiteName:container];
// Matchup
[defaults setObject:localMatchup forKey:@"KeyMatchup"];
NSArray *savedMatchup = [defaults objectForKey:@"KeyMatchup"];
NSLog(@"Default Matchup: %@", savedMatchup);
savedMatchup = matchupArray;
}
dispatch_async(dispatch_get_main_queue(), ^{
[self.tableView reloadData];
});
}
}];
}
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这是我在WatchKit应用程序中尝试的查询...
- (void)awakeWithContext:(id)context {
// GMT Date from Phone
NSDate *gmtNow = [NSDate date];
NSLog(@"GMT Now: %@", gmtNow);
// Query Parse
PFQuery *query = [self queryForTable];
[query whereKey:@"dateGame" greaterThanOrEqualTo:gmtNow];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (!error) {
NSMutableArray *localMatchup = [@[] mutableCopy];
for (PFObject *object in objects) {
// Add objects to local Arrays
[localMatchup addObject:[object objectForKey:@"matchup"]];
// App Group
NSString *container = @"group.com.me.off";
NSUserDefaults *defaults = [[NSUserDefaults alloc] initWithSuiteName:container];
// Matchup
[defaults setObject:localMatchup forKey:@"KeyMatchup"];
NSArray *savedMatchup = [defaults objectForKey:@"KeyMatchup"];
NSLog(@"Default Matchup: %@", savedMatchup);
savedMatchup = self.matchupArray;
}
dispatch_async(dispatch_get_main_queue(), ^{
[self.tableView reloadData];
});
}
}];
}
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但是我在这两条线上都有错误......
`PFQuery *query = [self queryForTable];`
`[self.tableView reloadData];`
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因为我无法做与table我猜测相关的完全相同的代码,但我只是不确定要将其更改为什么.
编辑:每个@cnoon回答添加代码
WatchKit InterfaceController.m:
我如何要求我的查询在这里运行? - (void)awakeWithContext:(id)context {[super awakeWithContext:context];
[WKInterfaceController openParentApplication:nil reply:^(NSDictionary *replyInfo, NSError *error) {
// What to put here?
NSLog(@"Open Parent Application");
}];
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-和-
苹果手机 AppDelegate.h
我怎么要求我PFQuery跑?
- (void)application:(UIApplication *)application handleWatchKitExtensionRequest:(NSDictionary *)userInfo reply:(void(^)(NSDictionary *replyInfo))reply {
// What to put here?
}
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UITableView在WatchKit应用程序中没有这样的东西.相反,您必须使用WKInterfaceTable.在继续之前,我还建议您阅读WatchKit编程指南中的文档.它将使您更好地了解作为有抱负的Apple Watch开发人员可用的所有工具集.
一旦你了解了a的来龙去脉WKInterfaceTable,你就会很快发现为什么你的方法存在缺陷有两个原因.首先,你没有reloadData方法.WatchKit中的替代方案是setNumberOfRows(_:withRowTypes:).然后,您需要遍历每一行并进行配置.
您将遇到问题的第二个原因是由于您的使用PFQuery.
这是一个侧面建议,所以接受或离开它.我从这里的经验来讲,已经构建了一个非常大的基于页面的Watch App,它与iOS App进行了大量的通信.
我建议你停止PFQuery在你的WatchKit扩展中使用s.原因是使用您的Watch App的用户只会打开应用程序一两秒钟.一切都会发生得非常快.因此,在用户终止Watch App之前,很难保证网络呼叫的成功.这使事情变得更加困难,但事实就是如此.
相反,您希望PFQuery在iOS应用程序上运行调用,并通过以下调用将该信息返回到Watch Extension:
WKInterfaceController- openParentApplication(_:reply :)UIApplicationDelegate- handleWatchKitExtensionRequest(_:reply :)您还可以使用MMWormhole或类似方法替代缓存PFQuery到共享应用程序组.下面是一个示例,说明如何让Watch Extension请求iOS应用程序运行PFQuery,将数据缓存在MMWormhole中,并在完成后通知Watch Extension.通过始终从缓存中读取数据,您可以获得一致的机制,即Watch Extension是否仍在运行以及关闭和重新打开.
InterfaceController.m
- (void)willActivate {
[super willActivate];
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 2.0 * NSEC_PER_SEC), dispatch_get_main_queue(), ^{
[WKInterfaceController
openParentApplication:@{@"pfquery_request": @"dumm_val"}
reply:^(NSDictionary *replyInfo, NSError *error) {
NSLog(@"User Info: %@", replyInfo);
NSLog(@"Error: %@", error);
if ([replyInfo[@"success"] boolValue]) {
NSLog(@"Read data from Wormhole and update interface!");
}
}];
});
}
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AppDelegate.m
- (void)application:(UIApplication *)application handleWatchKitExtensionRequest:(NSDictionary *)userInfo reply:(void (^)(NSDictionary *))reply {
if (userInfo[@"pfquery_request"]) {
NSLog(@"Starting PFQuery"); // won't print out to console since you're running the watch extension
// 1. Run the PFQuery
// 2. Write the data into MMWormhole (done in PFQuery completion block)
// 3. Send the reply back to the extension as success (done in PFQuery completion block)
reply(@{@"success": @(YES)});
}
reply(@{@"success": @(NO)});
}
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InterfaceController.swift
override func willActivate() {
super.willActivate()
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, Int64(2.0 * Float(NSEC_PER_SEC))), dispatch_get_main_queue()) {
WKInterfaceController.openParentApplication(["pfquery_request": "dummy_val"]) { userInfo, error in
println("User Info: \(userInfo)")
println("Error: \(error)")
if let success = (userInfo as? [String: AnyObject])?["success"] as? NSNumber {
if success.boolValue == true {
println("Read data from Wormhole and update interface!")
}
}
}
return
}
}
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AppDelegate.swift
func application(
application: UIApplication!,
handleWatchKitExtensionRequest userInfo: [NSObject : AnyObject]!,
reply: (([NSObject : AnyObject]!) -> Void)!)
{
if let pfqueryRequest: AnyObject = (userInfo as? [String: AnyObject])?["pfquery_request"] {
println("Starting PFQuery") // won't print out to console since you're running the watch extension
// 1. Run the PFQuery
// 2. Write the data into MMWormhole (done in PFQuery completion block)
// 3. Send the reply back to the extension as success (done in PFQuery completion block)
reply(["success": true])
}
reply(["success": false])
}
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希望这有助于打破从缓存中读取数据的一致方式以及将网络请求(或PFQueries)卸载到iOS应用程序的复杂性.
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