uno*_*aii 1 c# lambda expression
当我运行这段代码时
Expression left = Expression.Constant(10, typeof(int));
Expression right = Expression.Constant(10,typeof(int));
var method10 = typeof(Expression).GetMethod("Equal", new[] { typeof(Expression), typeof(Expression) });
Expression exp = Expression.Call(method10,left,right);
var lambda = Expression.Lambda<Func<bool>>(exp);
var compiled = lambda.Compile().DynamicInvoke();
Run Code Online (Sandbox Code Playgroud)
我收到以下错误
附加信息:类型的表达式'System.Int32'不能用于'System.Linq.Expressions.Expression'方法类型的参数'System.Linq.Expressions.BinaryExpression Equal(System.Linq.Expressions.Expression, System.Linq.Expressions.Expression)'
你不需要反思,除非我遗漏了一些东西:
Expression left = Expression.Constant(10, typeof(int));
Expression right = Expression.Constant(10,typeof(int));
Expression exp = Expression.Equal(left, right);
var lambda = Expression.Lambda<Func<bool>>(exp);
Run Code Online (Sandbox Code Playgroud)
显然你可以手动调用该int.Equals(int)方法......
var method10 = left.Type.GetMethod("Equals", new[] { right.Type });
Expression exp = Expression.Call(left, method10, right);
var lambda = Expression.Lambda<Func<bool>>(exp);
Run Code Online (Sandbox Code Playgroud)
但请注意,有一个微妙的区别:Expression.Equal将使用==运算符,而其他代码将使用Equals方法。
如果您确实想从字符串构建表达式:
string methodName = "Equal";
MethodInfo method10 = typeof(Expression).GetMethod(methodName, new[] { typeof(Expression), typeof(Expression) });
Expression exp = (Expression)method10.Invoke(null, new object[] { left, right });
var lambda = Expression.Lambda<Func<bool>>(exp);
Run Code Online (Sandbox Code Playgroud)
或者
ExpressionType type = (ExpressionType)Enum.Parse(typeof(ExpressionType), methodName);
var exp = Expression.MakeBinary(type, left, right);
Run Code Online (Sandbox Code Playgroud)
使用Enum.Parse
| 归档时间: |
|
| 查看次数: |
4155 次 |
| 最近记录: |