键盘功能有问题？

Question

我在执行代码的键盘上的返回键有问题.我在过去尝试过以下代码完美无缺:

func textFieldShouldReturn(textField: UITextField) -> Bool{
    textField.resignFirstResponder()
    valueOfLetter()
    return true;
}

但是,由于某种原因,该线路上存在错误valueOfLetter.

如果有必要,这是整个文件:

class ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
}

@IBOutlet weak var strWordValue: UILabel!
@IBOutlet weak var strInputField: UITextField!


func textFieldShouldReturn(textField: UITextField) -> Bool{
    textField.resignFirstResponder()
    valueOfLetter()
    return true;
}

 var TextField: UITextField!

    func valueOfLetter(inputLetter: String) -> Int {
        let alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

        for (index, letter) in alphabet {
            if letter = inputLetter.lowercaseString {
                return index + 1

                for character in word {
                    score += valueOfLetter(character)
                }
            }
        }

        return 0
    }
} 

错误是:"在调用参数#1中缺少参数

该行的另一个错误是for (index, letter) in alphabet:'String'不能转换为'([String,String])'

我不确定这些错误是什么意思或如何解决它们.

任何意见或建议将不胜感激.

提前致谢.

Answer 1

您的方法valueOfLetter需要一个参数,您需要使用参数调用它,否则它将无法工作.例如:

 valueOfLetter("x")

您的第二个错误正在发生,因为您使用的语法结构用于迭代带有数组的字典.使用内置enumerate函数迭代具有索引值的数组:

   for (index, letter) in enumerate(alphabet) {
        if letter = inputLetter.lowercaseString {
            return index + 1

            for character in word {
                score += valueOfLetter(character)
            }
        }
    }