如何在python 2.7中获取urllib2的状态代码

Question

如何在python 2.7中获取urllib2的状态码？我不想使用请求.我需要urllib2.

    request = urllib2.Request(url, headers=headers)
    contents = urllib2.urlopen(request).read()
    print request.getcode()
    contents = json.loads(contents) 

     <type 'exceptions.AttributeError'>, AttributeError('getcode',), <traceback object at 0x7f6238792b48>

谢谢

Answer 1

退后一步:

result = urllib2.urlopen(request)
contents = result.read()
print result.getcode()

Answer 2

使用 getcode()

>>> import urllib
>>> a=urllib.urlopen('http://www.google.com/asdfsf')
>>> a.getcode()
404
>>> 

对于 urllib2

try:
    urllib2.urlopen('http://www.google.com/asdfsf')
except urllib2.HTTPError, e:
    print e.code

将打印

404