我开始开发离子应用程序,我按照http://ionicframework.com/docs/guide/installation.html中的指南进行操作
以防万一:命令"离子平台添加ios"工作,我安装了android sdk.
当键入命令"ionic platform add android"时,我收到此错误:
Adding android project...
/Users/LihaiMac/.cordova/lib/npm_cache/cordova-android/3.7.1/package/bin/node_modules/q/q.js:126
throw e;
^
Package name must look like: com.company.Name
Error: /Users/LihaiMac/.cordova/lib/npm_cache/cordova-android/3.7.1/package/bin/create: Command failed with exit code 1
at ChildProcess.whenDone (/usr/local/lib/node_modules/cordova/node_modules/cordova-lib/src/cordova/superspawn.js:131:23)
at ChildProcess.emit (events.js:110:17)
at maybeClose (child_process.js:1008:16)
at Process.ChildProcess._handle.onexit (child_process.js:1080:5)
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我尝试在其他相关帖子中搜索答案,但没有成功..我会感谢任何帮助解决我的问题..
EeK*_*Kay 54
mladen5说的是正确的.您需要转到Cordova/Phonegap项目的config.xml并编辑ID以满足包名称期望.
该名称可以在ID属性中找到,并且在下面的示例配置中是"com.mydomainhere.appnamehere":
<?xml version='1.0' encoding='utf-8'?>
<widget id="com.mydomainhere.appnamehere" version="0.0.1" xmlns="http://www.w3.org/ns/widgets" xmlns:cdv="http://cordova.apache.org/ns/1.0">
<name>Awesome app</name>
<description>
The worlds most awesome app
</description>
<author email="your@email.com" href="http://www.anurlhere.com">
Author name
</author>
<content src="index.html" />
<access origin="*" />
</widget>
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Mla*_*vic 44
"包名必须如下:com.company.Name",该错误非常有用.您的包名称无效,可能以数字开头.
Android套餐规则: