使用链接矩阵和 networkx 绘制有向图

Question

我正在为一个学校项目进行页面排名，我有一个矩阵，其中行“i”代表从站点 j（行）到站点 i 的链接。（如果还不清楚，我会解释更多）。

当前部分是：

Z=[[0,1,1,1,1,0,1,0,0,0,0,0,0,0],[1,0,0,0,1,0,0,0,0,0,0,0,0,0],    [1,1,0,0,0,0,0,0,0,0,0,0,0,0],[1,0,1,0,0,0,0,0,0,0,0,0,0,0],[1,0,0,1,0,0,0,0,0,0,0,0,0,0],[1,0,0,0,0,0,0,1,0,1,0,0,0,0],[0,0,0,0,0,1,0,0,0,0,0,0,0,0],[0,0,0,0,0,1,1,0,1,0,0,0,0,0],[0,0,0,0,0,1,0,0,0,0,0,0,0,0],[0,0,0,0,0,0,0,0,1,0,1,1,1,1],[0,0,0,0,0,0,0,0,0,1,0,0,0,1],[0,0,0,0,0,0,0,0,0,1,1,0,0,0],[0,0,0,0,0,0,0,0,0,1,0,1,0,0],[0,0,0,0,0,0,0,0,0,1,0,0,1,0]]
A=np.matrix(Z)
G=nx.from_numpy_matrix(A,create_using=nx.MultiDiGraph())
pos=nx.circular_layout(G)
labels={}
for i in range (N):
    labels[i]=i+1
nx.draw_circular(G)
nx.draw_networkx_labels(G,pos,labels,font_size=15)

我遇到的问题是标签不在它们应该在的位置，似乎networkx只是按顺时针方向放置它们......

另外，我如何轻松地引导图形，以便从 j 到 i 的链接不会是从 i 到 j ？

谢谢！

Answer 1

import numpy as np
import matplotlib.pyplot as plt
import networkx as nx

Z = [[0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
     [1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
     [0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 1, 1],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0]]

G = nx.from_numpy_matrix(np.array(Z), create_using=nx.MultiDiGraph())
pos = nx.circular_layout(G)
nx.draw_circular(G)
labels = {i : i + 1 for i in G.nodes()}
nx.draw_networkx_labels(G, pos, labels, font_size=15)
plt.show()

产量

这个结果对我来说似乎是正确的。例如，请注意，标记的节点1具有指向2、3、4和5的有向边7。这对应于数组中第一行的那些Z[0]：

[0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0]

因为第一行对应于节点 1，并且该行中的那些出现在对应于节点2、3、4和5的列中7。