FiF*_*TeR 10 c# model-view-controller asp.net-mvc list
我正在尝试显示我在视图中创建的列表,但仍然得到:"传入字典的模型项的类型为'System.Collections.Generic.List 1[System.String]', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable
1 [Standings.Models.Teams]'."
我的控制器:
public class HomeController : Controller
{
Teams tm = new Teams();
public ActionResult Index()
{
var model = tm.Name.ToList();
model.Add("Manchester United");
model.Add("Chelsea");
model.Add("Manchester City");
model.Add("Arsenal");
model.Add("Liverpool");
model.Add("Tottenham");
return View(model);
}
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我的模特:
public class Teams
{
public int Position { get; set; }
public string HomeGround {get; set;}
public string NickName {get; set;}
public int Founded { get; set; }
public List<string> Name = new List<string>();
}
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我的看法:
@model IEnumerable<Standings.Models.Teams>
@{
ViewBag.Title = "Standings";
}
@foreach (var item in Model)
{
<div>
@item.Name
<hr />
</div>
}
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任何帮助,将不胜感激 :)
Far*_*yev 21
您的操作方法将模型类型视为List<string>
.但是,在你看来,你在等待IEnumerable<Standings.Models.Teams>
.您可以通过将视图中的模型更改为来解决此问题List<string>
.
但是,最好的方法是IEnumerable<Standings.Models.Teams>
从动作方法返回作为模型.然后,您不必在视图中更改模型类型.
但是,在我看来,你的模型没有正确实现.我建议你改成它:
public class Team
{
public int Position { get; set; }
public string HomeGround {get; set;}
public string NickName {get; set;}
public int Founded { get; set; }
public string Name { get; set; }
}
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然后,您必须将操作方法更改为:
public ActionResult Index()
{
var model = new List<Team>();
model.Add(new Team { Name = "MU"});
model.Add(new Team { Name = "Chelsea"});
...
return View(model);
}
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而且,您的观点:
@model IEnumerable<Standings.Models.Team>
@{
ViewBag.Title = "Standings";
}
@foreach (var item in Model)
{
<div>
@item.Name
<hr />
</div>
}
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