使用PHP $变量进行MySQL INSERT INTO

Question

我可以在那里使用$ variable$strSQL = "SELECT * FROM $person"; 但是我不能在那里使用$ variable$sql = "INSERT INTO $person . . .

`$person` 

不要工作......

有什么区别？我如何使用$ variable而不是表的名称(INSERT INTO table_name)

$sql = 'INSERT INTO $person (date, min, sec, count, temp, universal)
    VALUES("'.$date.'", "'.$min.'", "'.$sec.'", "'.$count.'", "'.$temp.'", "'.$universal.'")';
    if(!mysql_query($sql))
    {echo '<center><p><b>ERROR!</b></p></center>';}
    else
    {echo '<center><p><b>Its okay</b></p></center>';}
        }

解决:

mysql_query("INSERT INTO $person (date, min, sec, count, temp, universal) VALUES('$date', '$min', '$sec', '$count', '$temp', '$universal')") or die(mysql_error());

Answer 1

你可以这样使用

mysql_query("INSERT INTO `$person` VALUES(...) ")
or die(mysql_error());

你关闭了if和else错误

只是你可以试试这个

$sql = 'INSERT INTO `name`(date, min, sec, count, temp, universal)
        VALUES("'.$date.'", "'.$min.'", "'.$sec.'", "'.$count.'", "'.$temp.'", "'.$universal.'")';

$sql = 'INSERT INTO $person (date, min, sec, count, temp, universal)
    VALUES("'.$date.'", "'.$min.'", "'.$sec.'", "'.$count.'", "'.$temp.'", "'.$universal.'")';
    if(!mysql_query($sql)) {
    echo '<center><p><b>ERROR!</b></p></center>';
    }else{ 
    echo '<center><p><b>Its okay</b></p></center>';
    }
    }// so where this comes from ?