T-SQL LIKE与ASP.net参数中的通配符

Vin*_*ent 1 c# sql sql-server asp.net

在我的SQL语句中,我使用通配符.但是当我尝试选择某些东西时,它从不选择某些东西.当我在Microsoft SQL Server Management Studio中执行查询时,它可以正常工作.我究竟做错了什么?

单击处理程序

protected void btnTitelAuteur_Click(object sender, EventArgs e)
{
    cvalTitelAuteur.Enabled = true;
    cvalTitelAuteur.Validate();

    if (Page.IsValid)
    {
        objdsSelectedBooks.SelectMethod = "getBooksByTitleAuthor";
        objdsSelectedBooks.SelectParameters.Clear();
        objdsSelectedBooks.SelectParameters.Add(new Parameter("title", DbType.String));
        objdsSelectedBooks.SelectParameters.Add(new Parameter("author", DbType.String));
        objdsSelectedBooks.Select();
        gvSelectedBooks.DataBind();

        pnlZoeken.Visible = false;
        pnlKiezen.Visible = true;
    }
}
Run Code Online (Sandbox Code Playgroud)

在我的数据访问层中

public static DataTable getBooksByTitleAuthor(string title, string author)
{

    string sql = "SELECT 'AUTHOR' = tblAuthors.FIRSTNAME + ' ' + tblAuthors.LASTNAME, tblBooks.*, tblGenres.GENRE "
                + "FROM tblAuthors INNER JOIN tblBooks ON tblAuthors.AUTHOR_ID = tblBooks.AUTHOR_ID INNER JOIN tblGenres ON tblBooks.GENRE_ID = tblGenres.GENRE_ID "
                +"WHERE (tblBooks.TITLE LIKE '%@title%');";

    SqlDataAdapter da = new SqlDataAdapter(sql, GetConnectionString());
    da.SelectCommand.Parameters.Add("@title", SqlDbType.Text);
    da.SelectCommand.Parameters["@title"].Value = title;

    DataSet ds = new DataSet();
    da.Fill(ds, "Books");

    return ds.Tables["Books"];
}
Run Code Online (Sandbox Code Playgroud)

Joh*_*ers 6

试试这个:

string sql = "SELECT 'AUTHOR' = tblAuthors.FIRSTNAME + ' ' + tblAuthors.LASTNAME, tblBooks.*, tblGenres.GENRE "
           + "FROM tblAuthors INNER JOIN tblBooks ON tblAuthors.AUTHOR_ID = tblBooks.AUTHOR_ID INNER JOIN tblGenres ON tblBooks.GENRE_ID = tblGenres.GENRE_ID "
           +"WHERE (tblBooks.TITLE LIKE @title);";

SqlDataAdapter da = new SqlDataAdapter(sql, GetConnectionString());
da.SelectCommand.Parameters.Add("@title", SqlDbType.Text);
da.SelectCommand.Parameters["@title"].Value = "%" + title + "%";
Run Code Online (Sandbox Code Playgroud)