#include <stdlib.h>
#include <stdio.h>
using namespace std;
void main(){
char *resolutions[] = { "720x480", "1024x600", "1280x720", "1920x1080" };
int x = 0;
enum ResMode
{
p480,
p600,
p720,
p1080
};
ResMode res = p480;
printf("\nPlease enter the resolution you wish to use now by entering a number");
printf("\n480p[0], 600p[1], 720p[2], 1080p[3]");
gets(res);
printf("\nThe resolution you have selected is %s", resolutions[res]);
}
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所以基本上我想能够按1并让它从枚举中选择p600并将其作为1024x600放在下一行.我收到类型转换错误.我怎样才能解决这个问题?
看起来您想要将某些项目与其他项目相关联.通常在查找表或映射中描述关联.
std::map<ResMode, std::string> map_table =
{
{p480, string("720x480")},
{p600, string("1024x600")},
{p720, string("1280x720")},
{p1080, string("1920x1080")},
};
int main(void)
{
cout << map_table[p480] << "\n";
return EXIT_SUCCESS;
}
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同样,您可以将菜单选择映射到枚举.
编辑1
std::map<unsigned int, ResMode> selection_map =
{
{0, p480}, {1, p600}, {2, p720}, {3, p1080},
};
int main(void)
{
cout << "\n"
<< "Please enter the resolution you wish to use now by entering a number\n"
<<"480p[0], 600p[1], 720p[2], 1080p[3]";
unsigned int selection = 0;
cin >> selection;
if (selection < 4)
{
Resmode resolution_index = selection_map[selection];
cout << "You chose: "
<< map_table[resolution_index]
<< "\n";
}
return EXIT_SUCCESS;
}
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