如何在分配值时使用Swift循环整个字母表？

Question

我试图使用Swift在整个字母表中循环.唯一的问题是我想为每个字母赋值.

例如:a = 1,b = 2,c = 3,依此类推,直到我得到z = 26.

如何使用用户在使用先前分配给字母表中字母的值时键入的文本字段中的每个字母？

完成此操作后,如何将所有字母值相加以获得整个单词的总和.我正在寻找最简单的方法来实现这一点,但按照我希望的方式工作.

有什么建议？

提前致谢.

Answer 1

编辑/更新:Xcode 7.2.1•Swift 2.1.1

import UIKit

class ViewController: UIViewController {

    @IBOutlet weak var strWordValue: UILabel!
    @IBOutlet weak var strInputField: UITextField!


    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    @IBAction func sumLettersAction(sender: AnyObject) {
        strWordValue.text = strInputField.text?.wordValue.description

    }

}

扩展

extension String {
    var letterValue: Int {
        return Array("abcdefghijklmnopqrstuvwxyz".characters).indexOf(Character(lowercaseString))?.successor() ?? 0
    }
    var wordValue: Int {
        var result = 0
        characters.forEach { result += String($0).letterValue }
        return result
    }
}

func letterValue(letter: String) -> Int {
    return Array("abcdefghijklmnopqrstuvwxyz".characters).indexOf(Character(letter.lowercaseString))?.successor() ?? 0
}

func wordValue(word: String) -> Int {
    var result = 0
    word.characters.forEach { result += letterValue(String($0)) }
    return result
}


let aValue = letterValue("a")  // 1
let bValue = letterValue("b")  // 2
let cValue = letterValue("c")  // 3
let zValue = letterValue("Z")  // 26

let busterWordValue = wordValue("Buster") // 85
let busterWordValueString = wordValue("Buster").description // "85"

//

extension Character {
    var lowercase: Character { return Character(String(self).lowercaseString) }
    var value: Int { return Array("abcdefghijklmnopqrstuvwxyz".characters).indexOf(lowercase)?.successor() ?? 0 }
}
extension String {
    var wordValue: Int { return Array(characters).map{ $0.value }.reduce(0){ $0 + $1 } }
}

"Abcde".wordValue    // 15