列表上的Python正则表达式

Question

我正在尝试构建一个解析器并将结果保存为xml文件,但我有问题..

请问各位高手请看看我的代码？

追溯 :TypeError: expected string or buffer

import urllib2, re
from xml.dom.minidom import Document
from BeautifulSoup import BeautifulSoup as bs
osc = open('OSCTEST.html','r')
oscread = osc.read()
soup=bs(oscread)
doc = Document()
root = doc.createElement('root')
doc.appendChild(root)
countries = doc.createElement('countries')
root.appendChild(countries)
findtags1 = re.compile ('<h1 class="title metadata_title content_perceived_text(.*?)`</h1>', re.DOTALL |  re.IGNORECASE).findall(soup)
findtags2 = re.compile ('<span class="content_text">(.*?)</span>', re.DOTALL |  re.IGNORECASE).findall(soup)
for header in findtags1:
title_elem = doc.createElement('title')
countries.appendChild(title_elem)
header_elem = doc.createTextNode(header)
title_elem.appendChild(header_elem)
 for item in findtags2:
    art_elem = doc.createElement('artikel')
    countries.appendChild(art_elem)
    s = item.replace('<P>','')
    t = s.replace('</P>','')
    text_elem = doc.createTextNode(t)
    art_elem.appendChild(text_elem)    

print doc.toprettyxml()

Answer 1

你试图使用BeautifulSoup解析HTML是好的,但这不起作用:

re.compile('<h1 class="title metadata_title content_perceived_text(.*?)`</h1>',
           re.DOTALL | re.IGNORECASE).findall(soup)

您正在尝试使用正则表达式解析BeautifulSoup对象.相反,你应该在汤上使用findAll方法,如下所示:

regex = re.compile('^title metadata_title content_perceived_text', re.IGNORECASE)
for tag in soup.findAll('h1', attrs = { 'class' : regex }):
    print tag.contents

如果您确实希望使用正则表达式将文档解析为文本,则不要使用BeautifulSoup - 只需将文档读入字符串并解析即可.但我建议你花点时间了解BeautifulSoup是如何工作的,因为这是首选的方法.有关详细信息,请参阅文档.