我试图使用jquery函数将a 的内容加载<div>到<div>同一页面上的另一个内容.但是当函数触发时,它会将整个<HTML>文档加载到指定的文档中<div>.知道为什么会这样做吗?我的代码如下:
jQuery的:
function button1() {
$('#sidebar-content').fadeOut(function() {
$(this).load('#button1').fadeIn();
});
}
function button2() {
$('#sidebar-content').fadeOut(function() {
$(this).load('#button2').fadeIn();
});
}
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HTML:
<div id="content-holder">
<div id="main-content" class="float-holder">
<div id="inner">
<h1>BRAND TRUTH</h1>
<div id="flashcontent">
<div id="button1">
<div id="content">
<h1>Brand Truth</h1>
<p>What this basically means is our way of working, the process involved by both ourselves and our client.</p>
<p>When the truth wheel process is followed, the end result is so much stronger.</p>
</div>
</div>
<div id="button2">
<div id="content">
<h1>Button 2 Content</h1>
<p>Some other content</p>
<p>Some other content x2</p>
</div>
</div>
</div>
<script type="text/javascript">
// <![CDATA[
var so = new SWFObject("working.swf", "working", "400", "400", "9", "#FFFFFF");
so.write("flashcontent");
// ]]>
</script>
</div>
<div id="sidebar">
<div id="sidebar-content">
Replace Content Here!
</div>
</div>
</div><!-- end #main-content -->
</div><!-- end #content-holder -->
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.load()是一个通过AJAX加载远程网页的功能,你想要使用的.html()是这样的:
function button1() {
$('#sidebar-content').fadeOut(function() {
$(this).html($('#button1').html()).fadeIn();
});
}
function button2() {
$('#sidebar-content').fadeOut(function() {
$(this).html($('#button2').html()).fadeIn();
});
}
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.html()没有参数获取内部的html,所以我们从按钮获取它<div>,然后.html(string)在内部设置html,我们正在对结果进行处理.
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