在这种情况下,如何获得外部f​​oreach循环值？

Question

我试图从mysql数据中调用foreach循环中的所有值,并将值输入用于另一个mysql select语句.看下面的代码.它只能收集一个值.我想使用第一个foreach循环包括整个部分,但是,因为foreach值是个体的,我需要爆炸数组为PDO准备.所以,最后,我想知道一种从外部foreach循环中获取所有值的方法.欣赏.

//mysql connection code, remove because it is not relative to this question
foreach ($tag_id as $term){
	$term=$term['term'].' ';//use space to seprate each one
   
 }
	echo $term:// only can can one, how can I get all result from above foreach.
	$term=explode(' ', $term);
	
	
	$stm =$db->prepare("SELECT user_id FROM sign WHERE term IN (:term_0,:term_1,:ts.id, s.term, s.counter, os.user_id, os.id, COUNT(oserm_2,:term_3,:term_4,:term_5,:term_6,:term_7,:term_8,:term_9,:term_10)");

$term_0="$term[0]";
	$term_1="$term[1]";
	$term_2="$term[2]";
	$term_3="$term[3]";
	$term_4="$term[4]";
//following code is not relevive to this question.

Answer 1

如果您最后的目的是从您的值创建数组,为什么要将数据附加到字符串,只需将数据添加到数组然后直接使用它.

foreach ($tag_id as $term){
    $term_arr[]=$term['term'];

 }

 print_r($term_arr);

然后你可以使用

   $stm =$db->prepare("SELECT user_id FROM sign WHERE term IN (:term_0,:term_1,:ts.id, s.term, s.counter, os.user_id, os.id, COUNT(oserm_2,:term_3,:term_4,:term_5,:term_6,:term_7,:term_8,:term_9,:term_10)");

$term_0="$term_arr[0]";
    $term_1="$term_arr[1]";
    $term_2="$term_arr[2]";
    $term_3="$term_arr[3]";
    $term_4="$term_arr[4]";

Answer 2

假设$ tag_id是您的mysql查询的数组输出

$t = array();
foreach ($tag_id as $term){
    $t[]=$term['term']; // create array of terms 
 }
$str = "'".implode("','",$t)."'"; // make it a string, you can add here any other string you want to complete your query
    $stm =$db->prepare("SELECT `user_id` FROM `sign` WHERE `term` IN (".$str.");
$stm =$db->execute();