C++模板名称漂亮打印

Question

我需要打印缩进的模板名称以进行调试.例如,我想缩写名称,而不是单行:

boost::phoenix::actor<
    boost::phoenix::composite<
      boost::phoenix::less_eval,
      boost::fusion::vector<
        boost::phoenix::argument<0>,
        boost::phoenix::argument<1>,

我开始写自己的但是变得复杂了.有现成的解决方案吗？

如果没有,你能帮我完成我的实施吗？如果是的话,我会发布它.

谢谢

这就是typeid.name的样子,

boost::phoenix::actor<boost::phoenix::composite<boost::phoenix::less_eval, 
boost::fusion::vector<boost::phoenix::argument<0>, 
boost::phoenix::composite<boost::phoenix::multiplies_eval, 
boost::fusion::vector<boost::phoenix::argument<1>, boost::phoenix::argument<2>,
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void >, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_> > >

这是我的目标

 6 boost::phoenix::actor<
 7   boost::phoenix::composite<
 8     boost::phoenix::less_eval,
 9     boost::fusion::vector<
10       boost::phoenix::argument<0>,
11       boost::phoenix::composite<
12         boost::phoenix::multiplies_eval,
13         boost::fusion::vector<
14           boost::phoenix::argument<1>,
15           boost::phoenix::argument<2>,
16           boost::fusion::void_,
17           boost::fusion::void_,
18           boost::fusion::void_,
19           boost::fusion::void_,
20           boost::fusion::void_,
21           boost::fusion::void_,
22           boost::fusion::void_,
23           boost::fusion::void >, // indentation messed up
24           boost::fusion::void_,
25           boost::fusion::void_,
26           boost::fusion::void_,
27           boost::fusion::void_,
28           boost::fusion::void_,
29           boost::fusion::void_,
30           boost::fusion::void_,
31           boost::fusion::void_
32         >
33       >
34     >

这样我才能真正阅读宣言

Answer 1

怎么样，复制到剪贴板，然后

$ xclip -o | clang-format

例如，这需要 OP 的模板

boost::phoenix::actor <
boost::phoenix::composite<
    boost::phoenix::less_eval,
    boost::fusion::vector<
    boost::phoenix::argument<0>,
    boost::phoenix::composite<
        boost::phoenix::multiplies_eval,
        boost::fusion::vector<
        boost::phoenix::argument<1>, boost::phoenix::argument<2>,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void>,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_> > >

不理想，因为其中某处有错误。但是它可以很容易地找到错误（中间>后面的多余部分void应该移到最后）。如果我们修复它，我们会得到

boost::phoenix::actor<boost::phoenix::composite<
    boost::phoenix::less_eval,
    boost::fusion::vector<
        boost::phoenix::argument<0>,
        boost::phoenix::composite<
            boost::phoenix::multiplies_eval,
            boost::fusion::vector<
                boost::phoenix::argument<1>, boost::phoenix::argument<2>,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_>>>>>

Answer 2

当然不是最优雅的作品，但这应该能让你了解结束标签：

std::string indent(std::string str, const std::string &indent = "  ") {
    std::string indent_ = std::string("\n");
    size_t token = 0;

    while ((token = str.find_first_of("<>,", token)) != std::string::npos) {
        switch(str[token]) {
            case '<': indent_.append(indent);
            case ',': str.insert(token + 1, indent_);
                      break;
            case '>': indent_.erase(indent_.size() - indent.size());
                      str.insert(token, indent_);
        }

        token += indent_.size() + 1;            
        const size_t nw = str.find_first_not_of(" ", token);
        if(nw != std::string::npos) {
            str.erase(token, nw-token);
        }
    }

    return str;
}