执行突出显示的行后,以下操作失败.

字符串未被识别为有效的DateTime.
它突然发生,在12点左右工作......?现在是下午4:54而且没有去.到底他妈发生了什么?
您应该使用hh:mm:ss tt格式字符串 - HH用于24小时制,此时您说它是4AM ...但是PM作为AM/PM指示符.
基本上,使用hh与tt,或HH自身.
使用Noda Time,您将使用:
private static readonly LocalTimePattern TimePattern =
LocalTimePattern.CreateWithInvariantCulture("hh:mm:ss tt");
// TODO: Check this is what you want! We can't tell from your example.
private static readonly LocalDatePattern DatePattern =
LocalDatePattern.CreateWithInvariantCulture("dd/MM/yyyy");
private static readonly LocalDateTimePattern DateTimePattern =
LocalDatePattern.CreateWithInvariantCulture("yyyy-MM-dd HH:mm:ss");
public static string GetMergedDateTime(string dateText, string timeText)
{
// The Value property throws an exception if parsing failed. You can
// check that with the Success property first though.
LocalDate date = DatePattern.Parse(dateText).Value;
LocalTime time = TimePattern.Parse(timeText).Value;
LocalDateTime dateTime = date + time;
return DateTimePattern.Format(dateTime);
}
Run Code Online (Sandbox Code Playgroud)
请注意,返回可能更干净LocalDateTime- 在"自然"表示中尽可能多地完成工作,只在必要时使用字符串.