我用了Yii 2.
要明确:
也许以下的sql可以解释我想要的东西:
SELECT
c.content,
t.publish_status
FROM
content c, task t
WHERE
c.content LIKE '%keywordInContent%' AND
t.publish_status = 1 AND
c.id = t.content_id
ORDER BY
updated_at
LIMIT 20;
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这是我的控制器代码:
public function actionIndex()
{
$searchModel = new TaskSearch;
$dataProvider = $searchModel->search(Yii::$app->getRequest()->get());
return $this->render('index', [
'dataProvider' => $dataProvider,
'searchModel' => $searchModel,
]);
}
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和搜索模型代码:
public function search($params)
{
$query = Task::find()->trashed(Task::TRASHED_NO);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
$query->andFilterWhere(['publish_status' => $this->publish_status]);
return $dataProvider;
}
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我之前通过搜索like子句并将结果content_id添加到searchModel查询来解决它,代码如下:
if (!empty($this->keyword)) {
$contentIdArr = Content::find()->select('id')->where(['like', 'content', $this->keyword])->column();
if (empty($contentIdArr)) {
$contentIdArr = -1;
}
$query->andFilterWhere(['content_id' => $contentIdArr]);
}
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我想知道有没有办法构建我在Yii 2开始时编写的sql?
感谢帮助.
你能试一试吗:
public function search($params)
{
$query = Task::find()->trashed(Task::TRASHED_NO);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
if(!empty($this->keyword))
$query->leftJoin('content', 'content.id=task.content_id')
->andWhere(['publish_status' => 1])
->andWhere(['LIKE', 'content', $this->keyword])
->orderBy('updated_at');
return $dataProvider;
}
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但是我认为updated_at不应该是搜索的一部分.这更多是关于排序.在这里看一个例子.