我正在尝试编写Python脚本,它在Mac OS中使用python打印活动窗口的标题.
这是我的代码:
from AppKit import NSWorkspace
active_app_name = NSWorkspace.sharedWorkspace().frontmostApplication().localizedName()
print active_app_name
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此代码只打印应用程序的名称,如Google Chrome或firefox,但不打印标题.如何获得窗口的标题?
这是我使用 Quartz API 在 Mac OS X 上使用 Python 查找活动应用程序名称和窗口标题时使用的内容。
首先,我们需要根据需要添加导入:
if sys.platform == "darwin":
import applescript
from AppKit import NSWorkspace
from Quartz import (
CGWindowListCopyWindowInfo,
kCGWindowListOptionOnScreenOnly,
kCGNullWindowID
)
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然后我们可以通过下面的代码获取活动的应用程序名称和窗口标题:
def getActiveInfo(event_window_num):
try:
if sys.platform == "darwin":
app = NSWorkspace.sharedWorkspace().frontmostApplication()
active_app_name = app.localizedName()
options = kCGWindowListOptionOnScreenOnly
windowList = CGWindowListCopyWindowInfo(options, kCGNullWindowID)
windowTitle = 'Unknown'
for window in windowList:
windowNumber = window['kCGWindowNumber']
ownerName = window['kCGWindowOwnerName']
# geometry = window['kCGWindowBounds']
windowTitle = window.get('kCGWindowName', u'Unknown')
if windowTitle and (
event_window_num == windowNumber
or ownerName == active_app_name
):
# log.debug(
# 'ownerName=%s, windowName=%s, x=%s, y=%s, '
# 'width=%s, height=%s'
# % (window['kCGWindowOwnerName'],
# window.get('kCGWindowName', u'Unknown'),
# geometry['X'],
# geometry['Y'],
# geometry['Width'],
# geometry['Height']))
break
return _review_active_info(active_app_name, windowTitle)
if sys.platform == "win32":
(active_app_name, windowTitle) = _getActiveInfo_Win32()
return _review_active_info(active_app_name, windowTitle)
except:
log.error('Unexpected error: %s' % sys.exc_info()[0])
log.error('error line number: %s' % sys.exc_traceback.tb_lineno)
return 'Unknown', 'Unknown'
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