如何将参数传递给Node的Q库(denodeify)promise处理程序

Dan*_*Dan 3 javascript node.js promise q

在下面的代码中,我希望在调用a, b, cprocesshttprequest()将变量作为参数传递.

    var q = require("q");
    var request = require('request');

    function myfun()
    {
        var a, b, c;
        //do some work here
        var httprequest = q.denodeify(request);
        var httprequestpromise = httprequest(httpoptions);
        httprequestpromise.then(processhttprequest);
    }
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我试过httprequestpromise.then(processhttprequest.bind([a, b, c]));但没有运气.这是否由Q或任何其他承诺库支持.

jfr*_*d00 5

你可以.bind()像这样使用:

httprequestpromise.then(processhttprequest.bind(null, a, b, c));
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这将创建一个虚拟函数,将增加的参数a,bc之前调用processhttprequest().


或者,您可以使用您自己的存根函数手动执行此操作:

function myfun()
{
    var a, b, c;
    //do some work here
    var httprequest = q.denodeify(request);
    var httprequestpromise = httprequest(httpoptions);
    httprequestpromise.then(function(result) {
        return processhttprequest(a, b, c, result);
    });
}
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