python .lower()无法正常工作

Vic*_*zzi 1 python lowercase

我不知道我在做什么错,但是我的python代码中的.lower()函数不起作用!

这是一个愚蠢的代码,但不会降低单词的大小写:

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
         "x": 8, "z": 10}

def scrabble_score(word):
    word.lower()
    print word
    total =0
    for i in word:
        total += score[i]
    return total

print scrabble_score('Helix')    
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一些帮助?

EdC*_*ica 5

lower()由于字符串是不可变的,因此您必须将back 的结果分配给word :

In [152]:

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
         "x": 8, "z": 10}

def scrabble_score(word):
    word = word.lower() #<------ here assign back
    print(word)
    total =0
    for i in word:
        total += score[i]
    return total

print(scrabble_score('Helix'))

helix
15
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请参阅相关内容:为什么Python字符串是不可变的?使用它们的最佳实践