Rya*_*sch 6 .net validation expression-trees fluentvalidation simple-injector
在FluentValidation中是否有扩展或其他方式来推迟选择子验证器,具体取决于要验证的属性的类型/值?
我的情况是我有一个我要验证的Notification类.这个类有一个Payload属性,它可以是许多Payload类型之一,例如SmsPayload,EmailPayload等.这些Payload子类中的每一个都有自己的相关验证器,例如SmsPayloadValidator和EmailPayloadValidator.除上述内容外,核心库和个别通知提供者均未提及.从本质上讲,这意味着我可以根据需要添加提供程序,并使用IoC连接所有内容.
考虑以下类:
public class Notification
{
public Payload Payload { get; set; }
public IEnumerable<string> Details { get; set; }
}
public abstract class Payload
{
public string Message { get; set; }
public abstract string Type { get; }
}
public class SmsPayload : Payload
{
public List<string> Numbers { get; set; }
public string Region { get; set; }
public string Provider { get; set; }
}
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有一个Notification验证器和SmsPayloadValidator如下:
public class NotificationValidator : AbstractValidator<Notification>
{
public NotificationValidator(IValidator<Payload> payloadValidator)
{
RuleFor(notification => notification.Payload).NotNull().WithMessage("Payload cannot be null.");
RuleFor(notification => notification.Payload).SetValidator(payloadValidator);
}
}
public class SmsPayloadValidator : AbstractValidator<SmsPayload>
{
public SmsPayloadValidator()
{
RuleFor(payload => payload.Provider)
.Must(s => !string.IsNullOrEmpty(s))
.WithMessage("Provider is required.");
RuleFor(payload => payload.Numbers)
.Must(list => list != null && list.Any())
.WithMessage("Sms has no phone numbers specified.");
RuleFor(payload => payload.Region)
.Must(s => !string.IsNullOrEmpty(s))
.WithMessage("Region is required.");
}
}
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正如我所提到的,NotificationValidator所在的程序集不引用各个Payload验证程序类所在的程序集.所有接线都由Ioc(此项目的简单注入器)处理.
基本上我想做类似以下的事情 - 首先在Simple Injector中注册工厂回调:
container.Register<Func<Payload, IValidator<Payload>>>(() => (payload =>
{
if (payload.GetType() == typeof(SmsPayload))
{
return container.GetInstance<ISmsPayloadValidator>();
}
else if (payload.GetType() == typeof(EmailPayload))
{
return container.GetInstance<IEmailPayloadValidator>();
}
else
{
//something else;
}
}));
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这样我可以选择适当的验证器如下:
public class NotificationValidator : AbstractValidator<Notification>
{
public NotificationValidator(Func<Payload, IValidator<Payload>> factory)
{
RuleFor(notification => notification.Payload).NotNull().WithMessage("Payload cannot be null.");
RuleFor(notification => notification.Payload).SetValidator(payload => factory.Invoke(payload));
}
}
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有什么建议?或者有更好的方法来做我提出的建议吗?如果没有,我将分叉FluentValidation存储库并提交PR.
你可以通过避开工厂来使你的意图更加清晰.虽然最终结果可能与此方法相同,但您至少可以IValidator<Payload>
直接注射而不是Func<Payload, IValidator<Payload>>
.
创建一个名为的类PolymorphicValidator
.这将允许您以一致的方式重复此模式,并且如果您愿意,还可以提供后备基本验证器.这本质上是中推荐的"复合模式" 在这里简单注射器文档.
public class PolymorphicValidator<T> : AbstractValidator<T> where T : class
{
private readonly IValidator<T> _baseValidator;
private readonly Dictionary<Type, IValidator> _validatorMap = new Dictionary<Type,IValidator>();
public PolymorphicValidator() { }
public PolymorphicValidator(IValidator<T> baseValidator)
{
_baseValidator = baseValidator;
}
public PolymorphicValidator<T> RegisterDerived<TDerived>(IValidator<TDerived> validator) where TDerived : T
{
_validatorMap.Add(typeof (TDerived), validator);
return this;
}
public override ValidationResult Validate(ValidationContext<T> context)
{
var instance = context.InstanceToValidate;
var actualType = instance == null ? typeof(T) : instance.GetType();
IValidator validator;
if (_validatorMap.TryGetValue(actualType, out validator))
return validator.Validate(context);
if (_baseValidator != null)
return _baseValidator.Validate(context);
throw new NotSupportedException(string.Format("Attempted to validate unsupported type '{0}'. " +
"Provide a base class validator if you wish to catch additional types implicitly.", actualType));
}
}
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然后,您可以像这样注册您的验证器(可选择提供基类回退和其他子类验证器):
container.RegisterSingle<SmsPayloadValidator>();
//container.RegisterSingle<EmailPayloadValidator>();
container.RegisterSingle<IValidator<Payload>>(() =>
new PolymorphicValidator<Payload>(/*container.GetInstance<PayloadValidator>()*/)
.RegisterDerived(container.GetInstance<SmsPayloadValidator>())
/*.RegisterDerived(container.GetInstance<EmailPayloadValidator>() */);
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这将创建一个PolymorphicValidator
包含单子子验证器的单例(FluentValidation团队推荐使用单例).您现在可以IValidator<Payload>
按照第一个NotificationValidator
示例中所示进行注入.
public class NotificationValidator : AbstractValidator<Notification>
{
public NotificationValidator(IValidator<Payload> payloadValidator)
{
RuleFor(notification => notification.Payload)
.NotNull().WithMessage("Payload cannot be null.")
.SetValidator(payloadValidator);
}
}
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