解析Nmap结果BASH

Question

我正在写一个BASH脚本.从命令行我可以调用nmap,我想提取特定端口的ip.

$ nmap [ip]/24

Starting Nmap 6.47 ( http://nmap.org ) at 2015-02-26 01:59 PST
Nmap scan report for 192.168.56.1
Host is up (0.0012s latency).
Not shown: 500 closed ports, 499 filtered ports
PORT     STATE SERVICE
3689/tcp open  rendezvous

Nmap scan report for 192.168.56.101
Host is up (0.00042s latency).
Not shown: 998 closed ports
PORT   STATE SERVICE
21/tcp open  ftp
22/tcp open  ssh

我想要端口21的IP地址.在这个例子中,它将是192.168.56.101.如何从此返回中提取并将其保存到变量？谢谢

Answer 1

您可以使用xml输出并使用xmllint以下方法解析输出:

nmap -p 21 -oX - "$IP"/24 | xmllint --xpath '//port[@portid="21"]/state[@state="open"]/../../../address/@addr' -