OpenCV drawMatches 错误

Question

我的代码由一个部分组成，我在其中对一组匹配项进行排序并根据距离定义良好的匹配项。当我尝试 drawMatches 时，我收到一个错误：

OpenCV Error: Assertion failed (i1 >= 0 && i1 < static_cast<int>(keypoints1.size())) in drawMatches, file /home/user/OpenCV/opencv-2.4.10/modules/features2d/src/draw.cpp, line 207
terminate called after throwing an instance of 'cv::Exception'
  what():  /home/user/OpenCV/opencv-2.4.10/modules/features2d/src/draw.cpp:207: error: (-215) i1 >= 0 && i1 < static_cast<int>(keypoints1.size()) in function drawMatches

draw.cpp 文件显示：

// draw matches
for( size_t m = 0; m < matches1to2.size(); m++ )
{
     if( matchesMask.empty() || matchesMask[m] )
     {
          int i1 = matches1to2[m].queryIdx;
          int i2 = matches1to2[m].trainIdx;
          CV_Assert(i1 >= 0 && i1 < static_cast<int>(keypoints1.size()));
          CV_Assert(i2 >= 0 && i2 < static_cast<int>(keypoints2.size()));
          const KeyPoint &kp1 = keypoints1[i1], &kp2 = keypoints2[i2];
          _drawMatch( outImg, outImg1, outImg2, kp1, kp2, matchColor, flags );
     }
}

我的 drawMatches 调用如下：

Mat matchesImage;

drawMatches( im1, keypoints1, im2, keypoints2,
    good_matches, matchesImage, Scalar::all(-1), Scalar::all(-1),
    vector<char>(), DrawMatchesFlags::NOT_DRAW_SINGLE_POINTS );

有人可以帮我解释这个错误吗？

更新：

这是我的 good_matches 计算代码

double min_dist = 10000;
double max_dist = 0;

//-- Quick calculation of max and min distances between keypoints
for( int i = 0; i < descriptors1.rows; i++ ) { 
    double dist = matches[i].distance;
    if( dist < min_dist ) min_dist = dist;
    if( dist > max_dist ) max_dist = dist;
}

printf("-- Max dist : %f \n", max_dist );
printf("-- Min dist : %f \n", min_dist );

//-- Draw only "good" matches
std::vector< DMatch > good_matches;

for( int i = 0; i < descriptors1.rows; i++ ) {
    if( matches[i].distance <= max(2*min_dist, 0.02) ) { 
        good_matches.push_back( matches[i]); 
    }
}

for( int i = 0; i < (int)good_matches.size(); i++ ) {
    printf( "-- Good Match [%d] Keypoint 1: %d  -- Keypoint 2: %d  \n", 
        i, good_matches[i].queryIdx, good_matches[i].trainIdx ); 
}

cout << "number of good matches: " << (int)good_matches.size() << endl;;

//Draw matches and save file
Mat matchesImage;

drawMatches( im1, keypoints1, im2, keypoints2,
    good_matches, matchesImage, Scalar::all(-1), Scalar::all(-1),
    vector<char>(), DrawMatchesFlags::NOT_DRAW_SINGLE_POINTS );

更新 2：

BFMatcher matcher(NORM_L2, true);
vector<DMatch> matches;
matcher.match(descriptors1, descriptors2, matches);

Answer 1

一般来说，good_matches 是一个数组，它绑定keypoints1和keypoints2数组中的点。所以点keypoints1[good_matches[m].queryIdx]对应于点keypoints2[good_matches[m].trainIdx]。正如您所看到的，opencv 代码中的断言是有意义的。

看来问题出在 matches数组中。