R分号将列分隔为行

Question

我正在使用RStudio 2.15.0并使用XLConnect从3000多行和12列创建了一个Excel对象我试图将列分隔/拆分成行,但不知道这是否可行或如何操作.使用3列连接的下面数据示例.任何有关这方面的帮助都会很棒.

适用于其中两列的代码如下.

v1 <- with(df, tapply(PolId, Description,  FUN= function(x) {
x1 <- paste(x, collapse=";")
gsub('(\\b\\S+\\b)(?=.*\\b\\1\\b.*);', '',     x1, perl=TRUE)}))
library(stringr)
Description <- rep(names(v1),  str_count(v1, '\\w+'))
PolId <- scan(text=gsub(';+', ' ', v1), what='', quiet=TRUE)
data.frame(PolId, Description)  

样本数据

PolId   Description  Document.Type
ABC123;ABC456;ABC789;   TEST1  Pol1
ABC123;ABC456;ABC789;   TEST1  Pol1
ABC123;ABC456;ABC789;   TEST1  Pol1
AAA123; TEST1  End1
AAA123; TEST2  End2
ABB123;ABC123;  TEST3  End1
ABB123;ABC123;  TEST3  End1

我希望输出像这样(替换重复的Polid)

PolId   Description  Document.Type
ABC123  TEST1        Pol1
ABC456  TEST1        Pol1
ABC789  TEST1        Pol1
AAA123  TEST1        End1
AAA123  TEST2        End2
ABB123  TEST3        End1
ABC123  TEST3        End1

Answer 1

这是一个基础R解决方案.PolId使用strplit和拆分字段,并为每个这样的拆分字段cbind与相应的Description.这给出了我们rbind在一起的矩阵列表.最后设置列名称.

out <- do.call(rbind, Map(cbind, strsplit(DF$PolId, ";"), DF$Description))
colnames(out) <- colnames(DF)

赠送:

> out
      PolId    Description
 [1,] "ABC123" "TEST1"    
 [2,] "ABC456" "TEST1"    
 [3,] "ABC789" "TEST1"    
 [4,] "ABC123" "TEST1"    
 [5,] "ABC456" "TEST1"    
 [6,] "ABC789" "TEST1"    
 [7,] "ABC123" "TEST1"    
 [8,] "ABC456" "TEST1"    
 [9,] "ABC789" "TEST1"    
[10,] "AAA123" "TEST1"    
[11,] "AAA123" "TEST2"    
[12,] "ABB123" "TEST3"    
[13,] "ABC123" "TEST3"    
[14,] "ABB123" "TEST3"    
[15,] "ABC123" "TEST3" 

注意:我们使用它作为输入:

DF <-
structure(list(PolId = c("ABC123;ABC456;ABC789;", "ABC123;ABC456;ABC789;", 
"ABC123;ABC456;ABC789;", "AAA123;", "AAA123;", "ABB123;ABC123;", 
"ABB123;ABC123;"), Description = c("TEST1", "TEST1", "TEST1", 
"TEST1", "TEST2", "TEST3", "TEST3")), .Names = c("PolId", "Description"
), class = "data.frame", row.names = c(NA, -7L))

Answer 2

这是一个快速data.table可行的解决方案

library(data.table)
unique(setDT(df)[, .(PolId = unlist(strsplit(as.character(PolId), ";"))), by = Description])
#    Description  PolId
# 1:       TEST1 ABC123
# 2:       TEST1 ABC456
# 3:       TEST1 ABC789
# 4:       TEST1 AAA123
# 5:       TEST2 AAA123
# 6:       TEST3 ABB123
# 7:       TEST3 ABC123

根据您的编辑 - 另一个选项(如果您有两列以上)

library(splitstackshape)
unique(cSplit(df, "PolId", ";", "long"))
#     PolId Description Document.Type
# 1: ABC123       TEST1          Pol1
# 2: ABC456       TEST1          Pol1
# 3: ABC789       TEST1          Pol1
# 4: AAA123       TEST1          End1
# 5: AAA123       TEST2          End2
# 6: ABB123       TEST3          End1
# 7: ABC123       TEST3          End1