从Python解析subprocess.call()的输出

Question

我从我的Python代码中调用web服务:

response = subprocess.call(['curl', '-k', '-i', '-H' , 'content-type: application/soap+xml' ,'-d',  etree.tostring(tree), '-v' ,'https://world-service-dev.intra.aexp.com:4414/worldservice/CLIC/CaseManagementService/V1'])

该服务返回一条soap消息,如何解析soap消息并查明它是失败还是成功？

我尝试使用以下内容,但结果错误:

subprocess.check_output("curl -k --data "+etree.tostring(tree)+"@SampleRequest.xml -v  https://world-service-dev.intra.aexp.com:4414/worldservice/CLIC/CaseManagementService/V1",stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True)

Answer 1

不要PIPE只是调用check_output传递args列表并删除shell=True:

 out = subprocess.check_output(["curl", "-k","--data", etree.tostring(tree)+"@SampleRequest.xml", "-v",  "https://world-service-dev.intra.aexp.com:4414/worldservice/CLIC/CaseManagementService/V1"])

如果你得到一个非零的退出代码,你会得到一个CalledProcessError.