如何在没有数据库的情况下创建Yii2模型

Question

我想创建一个没有数据库的yii2模型.相反,数据是动态生成的,而不是存储的,只是作为json显示给用户.基本上,我只想得到一个非数据库模型工作的简单,基本的例子,但我找不到任何文档.

那么如何在没有数据库的情况下编写模型呢？我已经扩展,\yii\base\Model但我收到以下错误消息:

<?xml version="1.0" encoding="UTF-8"?>
<response>
   <name>PHP Fatal Error</name>
   <message>Call to undefined method my\app\models\Test::find()</message>
   <code>1</code>
   <type>yii\base\ErrorException</type>
   <file>/my/app/vendor/yiisoft/yii2/rest/IndexAction.php</file>
   <line>61</line>
   <stack-trace>
      <item>#0 [internal function]: yii\base\ErrorHandler->handleFatalError()</item>
      <item>#1 {main}</item>
   </stack-trace>
</response>

要实现find(),我必须返回一个数据库查询对象.

我的模型完全是空白的,我只是想找一个简单的例子来理解主体.

<?php
namespace my\app\models;

class Test extends \yii\base\Model{
}

Answer 1

这是Model我的一个项目.这Model与任何数据库都没有关联.

<?php
/**
 * Created by PhpStorm.
 * User: Abhimanyu
 * Date: 18-02-2015
 * Time: 22:07
 */

namespace backend\models;

use yii\base\Model;

class BasicSettingForm extends Model
{
    public $appName;
    public $appBackendTheme;
    public $appFrontendTheme;
    public $cacheClass;
    public $appTour;

    public function rules()
    {
        return [
            // Application Name
            ['appName', 'required'],
            ['appName', 'string', 'max' => 150],

            // Application Backend Theme
            ['appBackendTheme', 'required'],

            // Application Frontend Theme
            ['appFrontendTheme', 'required'],

            // Cache Class
            ['cacheClass', 'required'],
            ['cacheClass', 'string', 'max' => 128],

            // Application Tour
            ['appTour', 'boolean']
        ];
    }

    public function attributeLabels()
    {
        return [
            'appName'          => 'Application Name',
            'appFrontendTheme' => 'Frontend Theme',
            'appBackendTheme'  => 'Backend Theme',
            'cacheClass' => 'Cache Class',
            'appTour'    => 'Show introduction tour for new users'
        ];
    }
}

Model像其他任何一样使用它.例如view.php:

<?php
/**
 * Created by PhpStorm.
 * User: Abhimanyu
 * Date: 18-02-2015
 * Time: 16:47
 */

use abhimanyu\installer\helpers\enums\Configuration as Enum;
use yii\caching\DbCache;
use yii\caching\FileCache;
use yii\helpers\Html;
use yii\widgets\ActiveForm;

/** @var $this \yii\web\View */
/** @var $model \backend\models\BasicSettingForm */
/** @var $themes */

$this->title = 'Basic Settings - ' . Yii::$app->name;
?>

<div class="panel panel-default">
    <div class="panel-heading">Basic Settings</div>

    <div class="panel-body">

        <?= $this->render('/alert') ?>

        <?php $form = ActiveForm::begin([
                                        'id'                   => 'basic-setting-form',
                                        'enableAjaxValidation' => FALSE,
                                    ]); ?>

        <h4>Application Settings</h4>

        <div class="form-group">
            <?= $form->field($model, 'appName')->textInput([
                                                           'value'        => Yii::$app->config->get(
                                                               Enum::APP_NAME, 'Starter Kit'),
                                                           'autofocus'    => TRUE,
                                                           'autocomplete' => 'off'
                                                       ])
            ?>
        </div>

        <hr/>

        <h4>Theme Settings</h4>

        <div class="form-group">
            <?= $form->field($model, 'appBackendTheme')->dropDownList($themes, [
            'class'   => 'form-control',
            'options' => [
                Yii::$app->config->get(Enum::APP_BACKEND_THEME, 'yeti') => ['selected ' => TRUE]
            ]
        ]) ?>
    </div>

    <div class="form-group">
        <?= $form->field($model, 'appFrontendTheme')->dropDownList($themes, [
            'class'   => 'form-control',
            'options' => [
                Yii::$app->config->get(Enum::APP_FRONTEND_THEME, 'readable') => ['selected ' => TRUE]
            ]
        ]) ?>
    </div>

    <hr/>

    <h4>Cache Setting</h4>

    <div class="form-group">
        <?= $form->field($model, 'cacheClass')->dropDownList(
            [
                FileCache::className() => 'File Cache',
                DbCache::className()   => 'Db Cache'
            ],
            [
                'class'   => 'form-control',
                'options' => [
                    Yii::$app->config->get(Enum::CACHE_CLASS, FileCache::className()) => ['selected ' => TRUE]
                ]
            ]) ?>
    </div>

    <hr/>

    <h4>Introduction Tour</h4>

    <div class="form-group">
        <div class="checkbox">
            <?= $form->field($model, 'appTour')->checkbox() ?>
        </div>
    </div>

    <?= Html::submitButton('Save', ['class' => 'btn btn-primary']) ?>

    <?php $form::end(); ?>
</div>

Answer 2

使用模型的原因是对从某处获得的数据执行某种逻辑.模型可用于执行数据验证,返回模型的属性及其标签,并允许大量分配.如果您的数据模型不需要这些功能,请不要使用模型!

如果您不需要数据验证(即您没有通过表单或其他外部源更改任何数据),并且您不需要访问行为或事件,那么您可能只需要使用yii\base\Object.这将使您可以访问对象属性的getter和setter,这似乎就是您所需要的.

所以你的班级最终看起来像这样.我已经包括从另一个模型获取数据,以防你想要做的事情;

<?php
namespace my\app\models;
use \path\to\some\other\model\to\use\OtherModels;

class Test extends \yii\base\Object{

    public function getProperty1(){
        return "Whatever you want property1 to be";
    }

    public function getProperty2(){
        return "Whatever you want property2 to be";
    }

    public function getOtherModels(){
        return OtherModels::findAll();
    }

}

然后你会像这样简单地使用它;

$test = new Test;
echo $test->property1;
foreach ($test->otherModels as $otherModel){
    \\Do something
}

您尝试使用的函数find()仅与数据库相关,因此如果您扩展了yii\base\Model,yii\base\Component或yii\base\Object将无法使用该类. ,除非你想自己定义这样的功能.