验证PHPUnit中的HTTP响应代码

Question

我正在为返回HTTP响应代码的几种方法编写单元测试。我找不到断言HTTP响应代码的方法。也许我缺少明显的东西，或者我误解了有关PHPUnit的东西。

我正在使用PHPUnit 4.5稳定版。

类消息的相关部分：

public function validate() {
  // Decode JSON to array.
  if (!$json = json_decode($this->read(), TRUE)) {      
    return http_response_code(415);
  }
  return $json;
}

// Abstracted file_get_contents a bit to facilitate unit testing.
public $_file_input = 'php://input';

public function read() {
  return file_get_contents($this->_file_input);
}

单元测试：

// Load invalid JSON file and verify that validate() fails.
public function testValidateWhenInvalid() {
  $stub1 = $this->getMockForAbstractClass('Message');
  $path =  __DIR__ . '/testDataMalformed.json';
  $stub1->_file_input = $path;
  $result = $stub1->validate();
  // At this point, we have decoded the JSON file inside validate() and have expected it to fail.
  // Validate that the return value from HTTP 415.
  $this->assertEquals('415', $result);
}

PHPUnit返回：

1) MessageTest::testValidateWhenInvalid
Failed asserting that 'true' matches expected '415'.

我不确定为什么$ result返回'true'。。。特别是作为字符串值。同样不确定我的“预期”论点应该是什么。

Answer 1

根据文档，您可以http_response_code()不带任何参数的方法调用以接收当前响应代码。

<?php

http_response_code(401);
echo http_response_code(); //Output: 401

?>

因此，您的测试应如下所示：

public function testValidateWhenInvalid() {
    $stub1 = $this->getMockForAbstractClass('Message');
    $path =  __DIR__ . '/testDataMalformed.json';
    $stub1->_file_input = $path;
    $result = $stub1->validate();
    // At this point, we have decoded the JSON file inside validate() and have expected it to fail.
    // Validate that the return value from HTTP 415.
    $this->assertEquals(415, http_response_code()); //Note you will get an int for the return value, not a string
}