Chi*_*g B 6 sql sqlite sql-update
我有2个sqlite表:
table1(id INTEGER AUTOINCREMENT,状态TEXT,名称TEXT);
| id | status | name |
|----|-----------|------|
| 1 | pending | xyz |
| 2 | completed | abc |
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table2(状态TEXT,名称TEXT,trans_id INTEGER);
| trans_id | status | name |
|----------|-----------|------|
| 1 | refunded | cvb |
| 2 | cancelled | asd |
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我想更新从table2到table1的状态和名称,其中table1.id = table2.trans_id
我有这个问题:
UPDATE table1
SET status = (SELECT t2.status FROM table1 t1,table2 t2 WHERE t1.id = t2.trans_id) ,
name = (SELECT t2.name FROM table1 t1,table2 t2 WHERE t1.id = t2.trans_id)
WHERE id IN (SELECT trans_id FROM table1 t1,table2 t2 WHERE t1.id = t2.trans_id)
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它错误地填充了table1.这是结果table1
| id | status | name |
|----|----------|------|
| 1 | refunded | cvb |
| 2 | refunded | cvb |
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我的要求是:
| id | status | name |
|----|-----------|------|
| 1 | refunded | cvb |
| 2 | cancelled | asd |
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我的查询有什么问题?我怎样才能实现它?
我假设t2.trans_id是uniq或primary key在table2.如果没有,那么如果它返回多个结果,则更新查询将爆炸.在这种情况下,您需要使用更多过滤器,WHERE 或者TOP 1如果需要任何结果则使用.
UPDATE table1
SET status = (SELECT t2.status FROM table2 t2 WHERE t2.trans_id = id) ,
name = (SELECT t2.name FROM table2 t2 WHERE t2.trans_id = id)
WHERE id IN (SELECT trans_id FROM table2 t2 WHERE t2.trans_id= id)
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小智 5
如果 table2 中有 id 列,则之前的答案将失败。最好使用全名table1.id
UPDATE table1
SET status = (SELECT t2.status FROM table2 t2 WHERE t2.trans_id = table1.id) ,
name = (SELECT t2.name FROM table2 t2 WHERE t2.trans_id = table1.id)
WHERE id IN (SELECT trans_id FROM table2 t2 WHERE t2.trans_id= table1.id);
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