cba*_*los 4 mongodb mongodb-query
如果我有这样的文件:
{
"_id": ObjectId("54e6774a73a7edfefdb9e2bc"),
"information":"",
"__v":0,
"goalieRoster":{
"locked":[
],
"approved":[
{
"_id": ObjectId("548d49bad972605bf2d1f55a"), // find by this
}
],
"signedUp":[
{
"_id": ObjectId("548d49bad972605bf2d1f55a"),
}
],
"maxSize":2
},
"skaterRoster":{
"locked":[
],
"approved":[
],
"signedUp":[
],
"maxSize":26
},
"date":{
"updated":"2015-02-20T02:56:42.258Z",
"skate":""
}
}
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我如何approved
通过子文档的id 获取整个子文档?我认为我很接近,因为以下查询几乎可以满足我的需求.
db.roster.find(
{
"goalieRoster.approved._id": ObjectId("548d54e9576ddacc20f3a88e")
},
{
"goalieRoster.approved": 1
}
);
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它返回父文档和approved
嵌套在里面的数组内的匹配子文档,goalieRoster
如此
{
"_id" : ObjectId("54e6774a73a7edfefdb9e2bc"),
"goalieRoster" : {
"approved" : [
{
"_id" : ObjectId("548d54e9576ddacc20f3a88e"),
}
]
}
}
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问题是我想要的只是里面的子文档approved
.此外,有能够丢弃goalieRoster
,只是approved
,并将它看起来既在经批准的数组中goalieRoster
和skaterRoster
?
编辑:我正在寻找的结果就是这个
{
"_id" : ObjectId("548d54e9576ddacc20f3a88e"),
}
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sty*_*ane 12
您想要的是与$
操作员一起投影.
db.test.find({"goalieRoster.approved._id": ObjectId("548d49bad972605bf2d1f55a")},
{"goalieRoster.approved.$": true}
)
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结果
{
"_id" : "54e6774a73a7edfefdb9e2bc",
"goalieRoster" : { "approved" : [ { "_id" : "548d54e9576ddacc20f3a88e" } ] }
}
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