在Laravel 4.2中,我试图实现一个返回所有具有所有特定活动的用户的查询.截至目前,我有一个查询返回所有具有许多活动之一的用户:
//$selectedActivities being an array
$userByActivities = User::with('activities')
->whereHas('activities', function($query) use($selectedActivities){
$query->whereIn('id', $selectedActivities);
})->get();
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更清楚:给定的活动a,b,c.我正在寻找所有活动为AND b和c的用户.我的查询返回所有具有OR b OR c活动的用户.
谢谢您的帮助.
编辑:
lukasgeiter提供的解决方案导致以下查询:
select * from `users` where
(select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '7') >= 1
and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '3') >= 1
and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '1') >= 1
and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '2') >= 1
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鉴于Jarek Tkaczyk提供的解决方案:
$userByActivities = User::with('activities')
->whereHas('activities', function($query) use($selectedActivities) {
$query->selectRaw('count(distinct id)')->whereIn('id', $selectedActivities);
}, '=', count($selectedActivities))->get();
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对于类似的请求,导致以下查询:
select * from `users` where (select count(distinct id) from `activities`
inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id`
where `activity_user`.`user_id` = `users`.`id` and `id` in ('7', '3', '1', '2')) = 4
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你必须为此添加多个whereHas
:
$query = User::with('activities');
foreach($selectedActivities as $activityId){
$query->whereHas('activities', function($q) use ($activityId){
$q->where('id', $activityId);
});
}
$userByActivities = $query->get();
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小智 6
如果您遇到的Cardinality violation: 1241 Operand should contain 2 column(s)
问题是嵌套selectCount
添加到正常情况select count(*)
而不是覆盖现有选择,那么更改为$query->distinct()->whereIn('id', $selectedActivities);
对我来说是可行的,或者更改为$query->select(DB::raw(count(distinct id)))
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