如何使用Doctrine连接select语句中的字段

Question

我想知道如何连接DQL select语句中的两个字段与之间的一些文字.

我现在有这个,但没有运气......

$qb
            ->select('season.id, concat(competition.name, '-',season.name) AS specs')
            ->leftJoin('season.competition', 'competition')
            ->where('season.name LIKE :q')
            ->setParameter('q', '%'.$q.'%')
            ->setMaxResults($p)
        ;

Answer 1

我们不能在这里发送三个参数,但我们可以这样做,

$em = \Zend_Registry::get('em');
        $qb_1 = $em->createQueryBuilder();
        $q_1 = $qb_1->select( "reprt_abs.id" )
        ->addSelect( "CONCAT( CONCAT(reporter.firstname, ' '),  reporter.lastname)" )
        ->from( '\Entities\report_abuse', 'reprt_abs' )
        ->leftJoin( 'reprt_abs.User', 'reporter' )
        ->getQuery()->getResult();

这部分就是你想要的:

$ qb_1-> select("reprt_abs.id") - > addSelect("CONCAT(CONCAT(reporter.firstname,''),reporter.lastname)")

以下是我方的输出:

array (size=19)
  0 => 
    array (size=2)
      'id' => int 1
      1 => string 'Jaskaran Singh' (length=14)
  1 => 
    array (size=2)
      'id' => int 9
      1 => string 'Harsimer Kaur' (length=14)
  2 => 
    array (size=2)
      'id' => int 12
      1 => string 'Jaskaran Singh' (length=14)
  3 => 
    array (size=2)
      'id' => int 16
      1 => string 'Jaskaran Singh' (length=14)
  4 => 
    array (size=2)
      'id' => int 19
      1 => string 'Jaskaran Singh' (length=14)
  5 => 
    array (size=2)
      'id' => int 4
      1 => string 'shilpi jaiswal' (length=14)