%〜1在这个批处理文件中做了什么？

Question

我找到了这段代码,但有些部分我不明白.

这是我的代码:

Main.bat:

@echo off
set "CallCount=0"
set "Mood="
set /P "Mood=Your mood is: "
call Receive.bat "%Mood%"
rem *Random stuff*
set "Food="
set /P "Food=The food you want is: "
call Receive.bat "%Food%"
set "CallCount="

Receive.bat:

@echo off  
set /A CallCount+=1           
if "CallCount"=="2" goto Call2   
if not "%~1"=="" echo %1     <----
*Random Stuff*                   |
goto :EOF                        |---What is %~1 doing in this area?
:Call2                           |
if not "%~1"=="" echo %1     <----
rem Commands for second call.

编辑:这是一个使用call命令两次的文件.

Answer 1

%1是调用命令行的第一个参数.如果传递的参数有引号,则%1包括引号.在哪里,%~1提供带有引号的参数值.

这里有用的参考.