Col*_*Nik 22 query-builder yii2
我有一个任务 - 添加搜索模型搜索全名.全名是名字+姓氏.所以我需要构建查询
WHERE first_name LIKE '%var%' OR last_name LIKE '%var%'
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我能做到的唯一方法:
$query->andFilterWhere([
'OR',
'profiles.first_name LIKE "%' . $this->userFullName . '%" ',
'profiles.last_name LIKE "%' . $this->userFullName . '%"'
]);
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但我不喜欢它,因为它不安全.我不知道怎么...我认为有办法用yii2活动构建器构建这样的查询,我想得到结果像
$query->andFilterWhere(['LIKE', 'profiles.first_name', $this->userFullName]);
$query->andFilterWhere(['OR LIKE', 'profiles.last_name', $this->userFullName]);
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问题出在查询中,我可以使用数组作为属性将被comapred的值,但我不能使用数组作为要比较的属性列表.
要么
$subQuery1 = Profile::find()->Where(['LIKE', 'profiles.first_name', $this->userFullName]);
$subQuery2 = Profile::find()->Where(['LIKE', 'profiles.last_name', $this->userFullName]);
//i think its overloaded(3 queries insteadof 1 but still) and the final query
$query->andFilterWhere([
'OR',
$subQuery1,
$subQuery2
]);
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任何想法如何构建查询whithout"%"?
soj*_*oju 50
你应该尝试:
$query->andFilterWhere([
'or',
['like', 'profiles.first_name', $this->userFullName],
['like', 'profiles.last_name', $this->userFullName],
]);
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or
:类似于and
运算符,除了操作数使用连接OR
.例如,['or', ['type' => [7, 8, 9]], ['id' => [1, 2, 3]]
将生成(type IN (7, 8, 9) OR (id IN (1, 2, 3)))
.
阅读更多:http://www.yiiframework.com/doc-2.0/yii-db-queryinterface.html#where()-detail
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