Bla*_*man 688 javascript string split
我有一个逗号分隔的字符串,我想转换成一个数组,所以我可以循环它.
有内置的东西吗?
例如,我有这个字符串
var str = "January,February,March,April,May,June,July,August,September,October,November,December";
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现在想用逗号分割它并存储在Array对象中
Mat*_*chu 1164
var array = string.split(',');
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MDN参考,主要有助于limit
参数的可能意外行为.(提示:"a,b,c".split(",", 2)
出来["a", "b"]
,不是["a", "b,c"]
.)
pop*_*pop 127
注意你是否瞄准整数,如1,2,3,4,5.如果您打算在拆分字符串后将数组的元素用作整数而不是字符串,请考虑将它们转换为字符串.
var str = "1,2,3,4,5,6";
var temp = new Array();
// this will return an array with strings "1", "2", etc.
temp = str.split(",");
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添加这样的循环
for (a in temp ) {
temp[a] = parseInt(temp[a], 10); // Explicitly include base as per Álvaro's comment
}
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将返回一个包含整数而不是字符串的数组.
Jus*_*tme 32
嗯拆分是危险的imho,因为字符串总是可以包含逗号,请注意以下内容:
var myArr = "a,b,c,d,e,f,g,','";
result = myArr.split(',');
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那你怎么会混淆呢?你想要的结果是什么?一个数组:
['a', 'b', 'c', 'd', 'e', 'f', 'g', '\'', '\''] or
['a', 'b', 'c', 'd', 'e', 'f', 'g', ',']
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即使你逃脱逗号你也有问题.
快速摆弄这个:
(function($) {
$.extend({
splitAttrString: function(theStr) {
var attrs = [];
var RefString = function(s) {
this.value = s;
};
RefString.prototype.toString = function() {
return this.value;
};
RefString.prototype.charAt = String.prototype.charAt;
var data = new RefString(theStr);
var getBlock = function(endChr, restString) {
var block = '';
var currChr = '';
while ((currChr != endChr) && (restString.value !== '')) {
if (/'|"/.test(currChr)) {
block = $.trim(block) + getBlock(currChr, restString);
}
else if (/\{/.test(currChr)) {
block = $.trim(block) + getBlock('}', restString);
}
else if (/\[/.test(currChr)) {
block = $.trim(block) + getBlock(']', restString);
}
else {
block += currChr;
}
currChr = restString.charAt(0);
restString.value = restString.value.slice(1);
}
return $.trim(block);
};
do {
var attr = getBlock(',', data);
attrs.push(attr);
}
while (data.value !== '');
return attrs;
}
});
})(jQuery);
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随意使用/编辑:)
Jak*_*lde 26
split()方法用于将字符串拆分为子字符串数组,并返回新数组.
var array = string.split(',');
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vas*_*vas 25
str.split(',')
简单的人str.split(',')
没有太多智慧。以下是针对不同需求的一些升级。您可以根据自己的喜好自定义功能。
const str = "a, b,c, d ,e ,f,,g"
const num = "1, 2,3, 4 ,5 ,6,,7.495"
const mix = "a, 2,3, d ,5 ,f,,7.495,g"
console.log( str.split(',')
) // spaces NOT trimmed, empty values included
// ["a", " b", "c", " d ", "e ", "f", "", "g"]
console.log( str.split(/[ ,]+/)
) // spaces trimmed, empty values skipped
// ["a", "b", "c", "d", "e", "f", "g"]
console.log( str.split(/\s*,\s*/)
) // spaces trimmed, empty values NOT skipped
// ["a", "b", "c", "d", "e", "f", "", "g"]
console.log( num.split(',').map(Number)
) // numbers, empty values default to zero
// [1, 2, 3, 4, 5, 6, 0, 7.495]
console.log( num.split(/[ ,]+/).map(Number)
) // numbers, skips empty values
// [1, 2, 3, 4, 5, 6, 7.495]
console.log( mix.split(/\s*,\s*/)
.map(x => (x === '') ? '' : (isNaN(Number(x)) ? x : Number(x)) )
) // mixed values, empty values included
// ["a", 2, 3, "d", 5, "f", "", 7.495, "g"]
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JSON.parse
它可能感觉有点像 hack,但它很简单,并且大多数 Javascript 引擎都进行了高度优化。
它还有一些其他优点,例如支持嵌套列表。但也有缺点,例如要求输入格式正确的 JSON。
通过使用string.replace
类似于我string.split
上面使用的方式,您可以修复输入。在下面的前两个示例中,我自定义了空值的处理方式:
const num = "1, 2,3, 4 ,5 ,6,,7.495"
const mix = "a, 2,3, d ,5 ,f,7.495,g"
console.log( JSON.parse('['+num.replace(/,\s*,/,',0,')+']')
) // numbers, empty values default to zero
// [1, 2, 3, 4, 5, 6, 0, 7.495]
console.log( JSON.parse('['+num.replace(/,\s*,/,',')+']')
) // numbers, skips empty values
// [1, 2, 3, 4, 5, 6, 7.495]
console.log( JSON.parse('['+mix.replace(/(^|,)\s*([^,]*[^0-9, ][^,]*?)\s*(?=,|$)/g,'$1"$2"')+']')
) // mixed values, will ERROR on empty values
// ["a", 2, 3, "d", 5, "f", "7.495", "g"]
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use*_*213 15
请注意以下内容:
var a = "";
var x = new Array();
x = a.split(",");
alert(x.length);
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会警告1
BJ *_*tel 11
将逗号分隔后的字符串传递给此函数,它将返回数组,如果没有逗号分隔的字符串,则返回null.
function SplitTheString(CommaSepStr) {
var ResultArray = null;
if (CommaSepStr!= null) {
var SplitChars = ',';
if (CommaSepStr.indexOf(SplitChars) >= 0) {
ResultArray = CommaSepStr.split(SplitChars);
}
}
return ResultArray ;
}
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let str = "January,February,March,April,May,June,July,August,September,October,November,December"
let arr = str.split(',');
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它会导致:
["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
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如果您想将以下内容转换为:
["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
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这个:
"January,February,March,April,May,June,July,August,September,October,November,December";
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用:
str = arr.join(',')
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var array = (new Function("return [" + str+ "];")());
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它的接受字符串和对象串
var string = "0,1";
var objectstring = '{Name:"Tshirt", CatGroupName:"Clothes", Gender:"male-female"}, {Name:"Dress", CatGroupName:"Clothes", Gender:"female"}, {Name:"Belt", CatGroupName:"Leather", Gender:"child"}';
var stringArray = (new Function("return [" + string+ "];")());
var objectStringArray = (new Function("return [" + objectstring+ "];")());
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JSFiddle https://jsfiddle.net/7ne9L4Lj/1/
我知道这个问题已经回答了很长时间,但是我认为我的贡献对其他研究此主题的人将是有益的...
这是一个将字符串转换为数组的函数,即使列表中只有一项(没有分隔符)也是如此:
function listToAray(fullString, separator) {
var fullArray = [];
if (fullString !== undefined) {
if (fullString.indexOf(separator) == -1) {
fullAray.push(fullString);
} else {
fullArray = fullString.split(separator);
}
}
return fullArray;
}
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像这样使用它:
var myString = 'alpha,bravo,charlie,delta';
var myArray = listToArray(myString, ',');
myArray[2]; // charlie
var yourString = 'echo';
var yourArray = listToArray(yourString, ',');
yourArray[0]; // echo
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我创建此函数是因为split
如果字符串中没有分隔符(仅一项),则会引发错误
我遇到了类似的问题,但是由于我需要将csv转换为数组数组(每行是一个数组元素,内部具有一个由逗号分隔的项的数组),因此问题更加复杂。
最简单的解决方案(我敢打赌,更安全)是使用PapaParse(http://papaparse.com/),它具有“ no-header”选项,可将csv转换为数组数组,此外,它会自动检测到“ ”作为分隔符。
另外,它已在凉亭中注册,因此我只需要:
bower install papa-parse --save
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然后在我的代码中使用它,如下所示:
var arrayOfArrays = Papa.parse(csvStringWithEnters), {header:false}).data;
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我真的很喜欢它。
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