从PowerShell运行cmd.exe

Question

我正在尝试使用PowerShell运行一些单元测试.我有一个命令(有点)工作:

$output = & $vsTestPath $TestAssembly $logger $TestCaseFilter 2>&1

这样做的问题是标准输出和标准错误流没有以正确的顺序出现 - 它们混淆了.对此的一个解决方案(从这里)是使用cmd.exe,但我不能让它工作.我觉得我已经尝试了所有我能想到的东西.

这就是我所拥有的:

$vsTestPath = "C:\Program Files (x86)\Microsoft Visual Studio 12.0\Common7\IDE\CommonExtensions\Microsoft\TestWindow\vstest.console.exe"
$TestAssembly = "C:\IntegrationTesting\Test Application\Ads.Slms.IntegrationTesting.Web.Smartfill.dll"
$output = & cmd.exe /c $vsTestPath $TestAssembly 2`>`&1

最后一行不起作用.很奇怪,如果我有

$output = & cmd.exe /c $vsTestPath 2`>`&1

然后就跑了,但当然对我没用.这是问题的第二个参数.我试过的其他事情.我怎么能让它运行？

$output = & cmd.exe /c $vsTestPath $TestAssembly 2`>`&1
$output = & cmd.exe /c $vsTestPath,$TestAssembly 2`>`&1
$output = & cmd.exe /c "$vsTestPath" $TestAssembly 2`>`&1
$output = & cmd.exe /c """$vsTestPath""" $TestAssembly 2`>`&1
$output = & cmd.exe /c "$vsTestPath" "$TestAssembly" 2`>`&1
$output = & cmd.exe /c """$vsTestPath""" """$TestAssembly""" 2`>`&1

Answer 1

运行此PowerShell命令时

& cmd.exe /c $vsTestPath $TestAssembly 2`>`&1

PowerShell生成此命令行:

cmd.exe /c "C:\Program Files (x86)\BlaBlaBla.exe" "C:\IntegrationTesting\Test Application\BlaBlaBla.dll" 2>&1

PowerShell包含值$vsTestPath和$TestAssembly引号的值,因为它们包含空格,第一个字符本身不是引号.现在您必须了解cmd此命令行的处理方式(请参阅参考资料cmd /?):

If /C or /K is specified, then the remainder of the command line after
the switch is processed as a command line, where the following logic is
used to process quote (") characters:

    1.  If all of the following conditions are met, then quote characters
        on the command line are preserved:

        - no /S switch
        - exactly two quote characters
        - no special characters between the two quote characters,
          where special is one of: &<>()@^|
        - there are one or more whitespace characters between the
          two quote characters
        - the string between the two quote characters is the name
          of an executable file.

    2.  Otherwise, old behavior is to see if the first character is
        a quote character and if so, strip the leading character and
        remove the last quote character on the command line, preserving
        any text after the last quote character.

如您所见,我们有两个以上的引号,第一个字符是引号,因此cmd将从命令行中删除第一个和最后一个引号:

C:\Program Files (x86)\BlaBlaBla.exe" "C:\IntegrationTesting\Test Application\BlaBlaBla.dll 2>&1

现在你实际上从C:\Program一些参数开始,你很可能没有C:\Program.exe或C:\Program.cmd.解决方案:添加额外的报价以使cmd快乐:

& cmd.exe /c `" $vsTestPath $TestAssembly 2`>`&1 `"
cmd.exe /c " "C:\Program Files (x86)\BlaBlaBla.exe" "C:\IntegrationTesting\Test Application\BlaBlaBla.dll" 2>&1 "
"C:\Program Files (x86)\BlaBlaBla.exe" "C:\IntegrationTesting\Test Application\BlaBlaBla.dll" 2>&1