如何强制在WebView中单击的任何链接在Safari中打开？

Question

我在我的应用程序中有一个WebView,我希望在WebView中点击任何链接在Safari中打开(而不是WebView本身).

我正在Swift中开发应用程序.

这样做的最佳方法是什么？

Answer 1

这在Swift和Obj-C中完全相同:

首先,声明您的视图控制器符合 UIWebViewDelegate

class MyViewController: UIWebViewDelegate

然后webViewShouldStartLoadingWithRequest:navigationType:在View Controller中实现:

// Swift 1 & 2
func webView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    switch navigationType {
    case .LinkClicked:
        // Open links in Safari
        UIApplication.sharedApplication().openURL(request.URL)
        return false
    default:
        // Handle other navigation types...
        return true
    }
}

// Swift 3
func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    switch navigationType {
    case .linkClicked:
        // Open links in Safari
        guard let url = request.url else { return true }

        if #available(iOS 10.0, *) {
            UIApplication.shared.open(url, options: [:], completionHandler: nil)
        } else {
            // openURL(_:) is deprecated in iOS 10+.
            UIApplication.shared.openURL(url)
        }
        return false
    default:
        // Handle other navigation types...
        return true
    }
}

最后,设置你UIWebView的代表,例如,viewDidLoad在你的故事板中或在你的故事板中:

webView.delegate = self

Answer 2

针对swift 3进行了更新

func webView(_: UIWebView, shouldStartLoadWith: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
    if navigationType == UIWebViewNavigationType.linkClicked {
        UIApplication.shared.open(shouldStartLoadWith.url!, options: [:], completionHandler: nil)
        return false
    }
    return true
}

Answer 3

根据苹果文档中的建议

UIWebView 在 iOS 12 之后也被弃用

这是使用 Swift 5.3 和 WKWebiew 的解决方案

首先用 WKWebview 替换你的 UIWebview

然后符合WKNavigationDelegate并实现方法

这是代码

extension WebViewControllerImpl: WKNavigationDelegate {
    func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
        guard case .linkActivated = navigationAction.navigationType,
              let url = navigationAction.request.url
        else {
            decisionHandler(.allow)
            return
        }
        decisionHandler(.cancel)
        UIApplication.shared.openURL(url)
   }
}

然后为您的 wkWebView 设置“navigationDelegate”

wkWebView.navigationDelegate = self