Sta*_*tam 2 c++ arrays fortran 2d fortran-iso-c-binding
在C++和Fortran之间传递一个固定的2D数组工作正常,但是我编写的程序不是这样,它将2D动态数组从C++传递给Fortran.
C++方面
extern "C" {void array2d_(double **, int *, int *); }
using namespace std;
int main()
{
double **array;
int nx=3;
int ny=2;
int i,j;
cout << "Passing dynamic array from C to Fortran\n";
array = (double **) malloc(nx * sizeof(double *));
if(array == NULL)
{
fprintf(stderr, "out of memory\n");
exit;
}
for(i = 0; i < nx; i++)
{
array[i] = (double *) malloc(ny * sizeof(double));
if(array[i] == NULL)
{
fprintf(stderr, "out of memory\n");
exit;
}
}
for(i = 0; i < nx; i++)
{
for(j = 0; j < ny; j++)
{
array[i][j]=i+j+i*(2+j)+4; //random initialisation
cout << "array[" << i << "][" << j << "]=" << array[i][j] << " ";
}
cout << endl;
}
array2d_(array, &nx, &ny);
for(i = 0; i < nx; i++)
free(array[i]);
free(array);
return 0;
}
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fortran方面
subroutine array2d(arr,nx_C,ny_C) bind(C,name="array2d_")
use iso_c_binding
implicit none
integer (C_INT), intent(IN) :: nx_C,ny_C !array sizes from C
real (C_DOUBLE), intent(INOUT) :: arr(ny_C,nx_C)
integer :: k,l
print *, "This is in Fortran routine..."
do k = 1,ny_C
do l=1,nx_C
print *, "arr(",k,",",l,") = ", arr(k,l)
end do
end do
end subroutine array2d
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C++中的输出是
array[0][0]=4 array[0][1]=5
array[1][0]=7 array[1][1]=9
array[2][0]=10 array[2][1]=13
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而在Fortran中,输出是
arr( 1 , 1 ) = 1.7994937190948764E-305
arr( 1 , 2 ) = 7.1027035167764720E-251
arr( 1 , 3 ) = 9.8813129168249309E-324
arr( 2 , 1 ) = 5.4809152658772852E-317
arr( 2 , 2 ) = 1.5475240269406953E-314
arr( 2 , 3 ) = 0.0000000000000000
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所以这些值不能正确传递.
主要原因是你的C数组是一个锯齿状数组,它是一个分离1D数组的指针数组,而在Fortran中,你声明其中的参数是一个连续的2D数组.您必须在两个部分中使用相同的部分,最好在C中使用连续的数组.
只需要malloc一个大nx*ny缓冲区并设置指向行的指针而不是对它们进行alloacating.您可以在/sf/answers/413117001/中查看示例
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