如何使用Parametrized运行JUnit SpringJUnit4ClassRunner？

Question

由于重复@RunWith注释,以下代码无效:

@RunWith(SpringJUnit4ClassRunner.class)
@RunWith(Parameterized.class)
@SpringApplicationConfiguration(classes = {ApplicationConfigTest.class})
public class ServiceTest {
}

但是我如何结合使用这两个注释呢？

Answer 1

您可以使用Spring提供的SpringClassRule和SpringMethodRule

import org.junit.ClassRule;
import org.junit.Rule;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.junit.runners.Parameterized;
import org.springframework.test.context.junit4.rules.SpringClassRule;
import org.springframework.test.context.junit4.rules.SpringMethodRule;

@RunWith(Parameterized.class)
@ContextConfiguration(...)
public class MyTest {

    @ClassRule
    public static final SpringClassRule SPRING_CLASS_RULE = new SpringClassRule();

    @Rule
    public final SpringMethodRule springMethodRule = new SpringMethodRule();

    ...

Answer 2

至少有两个选项可以做到这一点:

1. 关注http://www.blog.project13.pl/index.php/coding/1077/runwith-junit4-with-both-springjunit4classrunner-and-parameterized/

   您的测试需要看起来像这样:

    @RunWith(Parameterized.class)
    @ContextConfiguration(classes = {ApplicationConfigTest.class})
    public class ServiceTest {
   
        private TestContextManager testContextManager;
   
        @Before
        public void setUpContext() throws Exception {
            //this is where the magic happens, we actually do "by hand" what the spring runner would do for us,
           // read the JavaDoc for the class bellow to know exactly what it does, the method names are quite accurate though
          this.testContextManager = new TestContextManager(getClass());
          this.testContextManager.prepareTestInstance(this);
        }
        ...
    }
   

2. 有一个github项目https://github.com/mmichaelis/spring-aware-rule,它建立在以前的博客上,但是以一种通用的方式增加了支持

   @SuppressWarnings("InstanceMethodNamingConvention")
   @ContextConfiguration(classes = {ServiceTest.class})
   public class SpringAwareTest {
   
       @ClassRule
       public static final SpringAware SPRING_AWARE = SpringAware.forClass(SpringAwareTest.class);
   
       @Rule
       public TestRule springAwareMethod = SPRING_AWARE.forInstance(this);
   
       @Rule
       public TestName testName = new TestName();
   
       ...
   }
   

因此,您可以拥有一个实现其中一种方法的基本类,以及从中继承的所有测试.