Sys*_*Lol 5 sql t-sql sql-server sql-server-2005
我们有一个表,表示与实体(称为项目)关联的值树,其中 ParentID 列指行父级的 id 列。id 列是一个自动递增的 IDENTITY 列和主键。根节点的 ParentID 为 0。
我们希望能够克隆给定项目的数据,并让生成的 ParentID 引用复制值的适当新 ID,以满足示例下面描述的限制。
例如,复制下表中 ProjectID 611 的数据:
id ProjectID Value ParentID
--------------------------------------------------
1 611 Animal 0
2 611 Frog 1
13 611 Cow 1
14 611 Jersey Cow 13
25 611 Plant 0
29 611 Tree 25
31 611 Oak 29
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应该导致:
id ProjectID Value ParentID
--------------------------------------------------
1 611 Animal 0
2 611 Frog 1
13 611 Cow 1
14 611 Jersey Cow 13
25 611 Plant 0
29 611 Tree 25
31 611 Oak 29
32 612 Animal 0
33 612 Frog 32
34 612 Cow 32
35 612 Jersey Cow 34
36 612 Plant 0
37 612 Tree 36
38 612 Oak 37
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限制:
CTE 可以很好地与 SQL Server 2005 配合使用MERGE
,但在 SQL Server 2005 中会出现问题。对于之前的误导性评论,我们深表歉意。
下面展示了如何克隆项目(具有多棵树)并修复起源以将新森林与旧森林分开。请注意,它不依赖于 Id 的任何特定排列,例如它们不需要是密集的、单调递增的……。
-- Sample data.
declare @Projects as Table
( Id Int Identity, ProjectId Int, Value VarChar(16), ParentId Int Null );
insert into @Projects ( ProjectId, Value, ParentId ) values
( 611, 'Animal', 0 ),
( 611, 'Frog', 1 ),
( 611, 'Cow', 1 ),
( 611, 'Jersey Cow', 3 ),
( 611, 'Plant', 0 ),
( 611, 'Tree', 5 ),
( 611, 'Oak', 6 );
-- Display the raw data.
select * from @Projects;
-- Display the forest.
with IndentedProjects ( Id, ProjectId, Value, ParentId, Level, Path ) as
( -- Start with the top level rows.
select Id, ProjectId, Value, ParentId, 0, Convert( VarChar(1024), Right( '000' + Convert( VarChar(4), Id ), 4 ) )
from @Projects
where ParentId = 0
union all
-- Add the children one level at a time.
select P.Id, P.ProjectId, P.Value, P.ParentId, IP.Level + 1, Convert( VarChar(1024), IP.Path + '<' + Right( '000' + Convert( VarChar(4), P.Id ), 4 ) )
from IndentedProjects as IP inner join
@Projects as P on P.ParentId = IP.Id
)
select Space( Level * 2 ) + Value as [IndentedValue], Id, ProjectId, Value, ParentId, Level, Path
from IndentedProjects
order by Path;
-- Clone the project.
declare @OldProjectId as Int = 611;
declare @NewProjectId as Int = 42;
declare @Fixups as Table ( OldId Int, [NewId] Int );
begin transaction -- With suitable isolation since the hierarchy will be invalid until we apply the fixups!
insert into @Projects
output Inserted.ParentId, Inserted.Id
into @Fixups
select @NewProjectId, Value, Id -- Note that we save the old Id in the new ParentId.
from @Projects as P
where ProjectId = @OldProjectId;
-- Apply the fixups.
update PNew
set ParentId = IsNull( FNew.[NewId], 0 )
-- Output the fixups just to show what is going on.
output Deleted.Id, Deleted.ParentId as [ParentIdBeforeFixup], Inserted.ParentId as [ParentIdAfterFixup]
from @Fixups as F inner join
@Projects as PNew on PNew.Id = F.[NewId] inner join -- Rows we need to fix.
@Fixups as FOld on FOld.OldId = PNew.ParentId inner join
@Projects as POld on POld.Id = FOld.OldId left outer join
@Fixups as FNew on FNew.OldId = POld.ParentId;
commit transaction;
-- Display the forest.
with IndentedProjects ( Id, ProjectId, Value, ParentId, Level, Path ) as
( -- Start with the top level rows.
select Id, ProjectId, Value, ParentId, 0, Convert( VarChar(1024), Right( '000' + Convert( VarChar(4), Id ), 4 ) )
from @Projects
where ParentId =0
union all
-- Add the children one level at a time.
select P.Id, P.ProjectId, P.Value, P.ParentId, IP.Level + 1, Convert( VarChar(1024), IP.Path + '<' + Right( '000' + Convert( VarChar(4), P.Id ), 4 ) )
from IndentedProjects as IP inner join
@Projects as P on P.ParentId = IP.Id
)
select Space( Level * 2 ) + Value as [IndentedValue], Id, ProjectId, Value, ParentId, Level, Path
from IndentedProjects
order by Path;
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