这个HQL查询有什么问题？

Question

我遇到了一个hibernate错误,或者我有一个错误,我没有看到:

select enty.number from EntityAliasName enty
  where enty.myId in
  (
    select cons.myId from Consens cons where cons.number in
    (
      select ord.number from Orders ord where ord.customer = :customer 
      and ord.creationDate <
      (
        select max(ord.creationDate) from Orders ord where ord.customer = :customer
      )
    )
  )

我得到的是以下内容:

org.hibernate.util.StringHelper.root(StringHelper.java:257)

Caused by: java.lang.NullPointerException
        at org.hibernate.util.StringHelper.root(StringHelper.java:257)
        at org.hibernate.persister.entity.AbstractEntityPersister.getSubclassPropertyTableNumber(AbstractEntityPersister.java:1391)
        at org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns(BasicEntityPropertyMapping.java:54)
        at org.hibernate.persister.entity.AbstractEntityPersister.toColumns(AbstractEntityPersister.java:1367)
        at org.hibernate.hql.ast.tree.FromElement.getIdentityColumn(FromElement.java:320)
        at org.hibernate.hql.ast.tree.IdentNode.resolveAsAlias(IdentNode.java:154)
        at org.hibernate.hql.ast.tree.IdentNode.resolve(IdentNode.java:100)
        at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:117)
        at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:113)
        at org.hibernate.hql.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:854)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRef(HqlSqlBaseWalker.java:1172)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRefLhs(HqlSqlBaseWalker.java:5167)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRef(HqlSqlBaseWalker.java:1133)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:1993)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:1932)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1476)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:580)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:288)
        at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:231)
        at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254)
        at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185)
        at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136)
        at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
        at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
        at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:94)
        at org.hibernate.impl.SessionFactoryImpl.checkNamedQueries(SessionFactoryImpl.java:484)
        at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:394)
        at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1341)

使用:Hibernate 3.3.2.GA/postgresql

---

更新:

我试图通过尝试为自己的子句执行每个子子来解决错误.我想通过执行以下操作得到了同样的异常:

select enty.number from EntityAliasName enty

但如果我执行以下它工作:

select number from EntityAliasName enty

所以现在问题,为什么？

也许我应该提一下这EntityAliasName是一个通过以下方式定义的实体别名:

<class name="package.EntityName"
         table="entities"
        entity-name="EntityAliasName"
        mutable="false"> ... </class>

---

更新2:

我找到了解决这个问题的方法.我的POJO以这种方式映射:

<class name="package.EntityName"
             table="entities"
            entity-name="EntityAliasName"
            mutable="false">

  <composite-id>
    <key-property name="val1" column="val1" type="long"/>
    <key-property name="val2" column="val2" type="integer"/>
  </composite-id>

  <property name="id" column="entity_id" type="string" length="255" not-null="true"/>

  ...

</class>

在拥有复合ID并使用Anthony Patricio报告的名为id:HHH-1851的属性时会出现问题.更改属性名称以解决问题:identityId

感谢mdma将我指向了正确的方向.

Answer 1

我找到了解决该问题的方法。我的POJO是这样映射的：

<class name="package.EntityName"
             table="entities"
            entity-name="EntityAliasName"
            mutable="false">

  <composite-id>
    <key-property name="val1" column="val1" type="long"/>
    <key-property name="val2" column="val2" type="integer"/>
  </composite-id>

  <property name="id" column="entity_id" type="string" length="255" not-null="true"/>

  ...

</class>

有一种具有复合ID并使用指定属性时的问题id：HHH-1851报由安东尼·帕特里西奥。将属性名称从更改id为entityId可解决问题：

<property name="entityId" column="entity_id" 
type="string" length="255" not-null="true"/>

感谢mdma为我指出正确的方向。

刚刚复制了我上面更新中的答案，以将其作为答案关闭并保持接受率上升