Shw*_*eta 7 action controller popover ipad
我有一个拆分View控制器,左侧有一个表视图控制器.当我单击表格单元格的详细信息披露按钮时,如何在弹出窗口中显示操作表?
Ibr*_*rim 15
试试这个 :
UIActionSheet *popupSheet = [[UIActionSheet alloc] initWithTitle:@"Title"
delegate:self
cancelButtonTitle:@"Cancel"
destructiveButtonTitle:@"No Way !"
otherButtonTitles:nil];
popupSheet.actionSheetStyle = UIActionSheetStyleBlackOpaque;
UIButton * disclosureButton = (UIButton *)cell.accessoryView;
[popupSheet showFromRect:disclosureButton.bounds inView:cell.accessoryView animated:YES];
[popupSheet release];
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所述UIActionSheet文档指出的showFromRect:inView:animated:方法:
在弹出窗口中显示操作表,其中箭头指向视图的指定矩形(在我们的示例中为详细信息公开按钮).弹出窗口不与指定的矩形重叠.