Cron syntax error near unexpected token

Question

Moved the site to another server. Add file statistic.php to the ?ron to perform. Only this Cron that does not like something. Write errors:

/home/site/www/statistic.php: line 1: ?php: No such file or directory
/home/site/www/statistic.php: line 2: syntax error near unexpected token `"bd.php"'
/home/site/www/statistic.php: line 2: `include ("bd.php");

There is my code

<?php
include ("bd.php");

    $result = mysql_query("SELECT MAX(id) FROM statistic_dep",$db);
    $myrow1 = mysql_fetch_array($result);
    $last_id=$myrow1[0];
...

Answer 1

确保您将脚本作为 php 脚本而不是 bash 脚本执行。

你的 crontab 应该是这样的：

* * * * * /usr/bin/php -f /path/to/file.php

作为 php 执行脚本的另一种方法是在第一行添加 shebang：

#!/usr/bin/php
<?php ...